anonymous
  • anonymous
Physics Question!: Can you help me find the velocities in the x and y direction when a ball is thrown a distance of 9.14 meters and the amount of time it took to land in another person's hand is 1.37 seconds. Use kinematics please.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
vel. at which time. tell me the way of throwing. is it horizontally or vertically or parabolic.
anonymous
  • anonymous
initial velocities, and parabolic.
anonymous
  • anonymous
here the horizontal distance(R) it travel is =initial horizontal vel.(Ux) * total time taken(T) R =Ux*T Ux=R/T=9.14/1.37 =6.67 m/s now the total vertical displacement is zero as it start from the ground & end with it. vertical displacement(H) =Uy*T-1/2(a*T^2) (Uy=initial vertical vel. ,a=vert. acc. = g=9.8) H=Uy*T -1/2( g*T^2) 0 =Uy*1.37 -0.5*9.8*1.37*1.37 Uy =9.19/1.37= 6.713 m/s so Ux=6.67 m/s Uy= 6.713 m/s

Looking for something else?

Not the answer you are looking for? Search for more explanations.