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anonymous
 5 years ago
an archer stands 40.0m from the target. if the arrow is shot horizontally with a velocity of 90.0 m/s, how far above the bull's eye must she aim to compensate for gravity pulling her arrow downward?
anonymous
 5 years ago
an archer stands 40.0m from the target. if the arrow is shot horizontally with a velocity of 90.0 m/s, how far above the bull's eye must she aim to compensate for gravity pulling her arrow downward?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0It takes less then .5 secs for it to reach the bulls eye, so my best guess is just aim for the bulls eye :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.080/81 m. is it correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Essentially, we need to determine how far gravity pulls the arrow during the time it takes to hit the target. The arrow is in flight for .444 seconds (40m/90m/s). Use the following equation, which can be derived by differential equations: xx0 = v0*t+.5a*t^2. Since the arrow was shot horizontally (all velocity goes into the xdirection), we know that there is no initial velocity in the ydirection. Thus, v0 = 0, and the eqn becomes xx0=.5*a*t^2. Assuming the arrow was fired on earth, a = 9.81m/s^2. Plug this and time into the eqn, and you get xx0=0.968m. This is the distance the target needs to be placed beneath the arrow. Think 1m is too large? Drop a coin, and measure how far it falls in .45 seconds.
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