anonymous
  • anonymous
Solve the given equation and indicate the number of values of θ sach that 0≤θ<2π ,that satisfy the iquation; Sina=½ 3^½
Mathematics
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anonymous
  • anonymous
Solve the given equation and indicate the number of values of θ sach that 0≤θ<2π ,that satisfy the iquation; Sina=½ 3^½
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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amistre64
  • amistre64
Is the equation: sin(a) = sqrt(3)/2 ? There are 2 angles that have a positive (sin) of sqrt(3)/2 in the unit circle. To solve the equation: we use the (sin inverse) functions; they take a number and spit back an angle. sin(a) = sqrt(3)/2 sin-1(sin(a)) = sin-1(sqrt(3)/2) a = sin-1(sqrt(3)/2) a = pi/3 Now the issue here is that sin-1 only gives you an angle between (-pi/2) and (pi/2) so you have to revert back to the original question to ALL the angles. 60 degrees (pi/3) and, 120 degrees (2pi/3) Does that make sense?
anonymous
  • anonymous
Equation is sina=plus,minus 1/2 sqrt(3)?
amistre64
  • amistre64
If it is sin(a) = +- sqrt(3)/2 then there are 4 angles that we can use; and they all have a reference angle of (60 degrees). In quadrant 1 we have (pi/3) which is 60 degrees In quadrant 2 we have (2pi/3) which is 120 degrees In quadrant 3 we have (4pi/3) which is 240 degrees In quadrant 4 we have (5pi/3) which is 320 degrees

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anonymous
  • anonymous
Make sense.Thank you

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