## anonymous 5 years ago integrate 1/(4+x^2) x=0 , x=(2/squareroot3)

1. anonymous

$\int\limits_{0}^{2/\sqrt{3}}1/(4+x ^{2})$ =(1/4)*1/(1+(x/2)^2) $=1/4 *\tan^{-1} x/2$(x=0 to 2/root3) so by putting the value of x u will get the ans as $\pi/6$

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