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anonymous
 5 years ago
i need the steps in simplifying:
square root of 27x^8y^5
anonymous
 5 years ago
i need the steps in simplifying: square root of 27x^8y^5

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can break it up like this: sqrt(27)*sqrt(x^8)*sqrt(y^5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you have something raised to an exponent, such as x^8, you can subtract 2 from the exponent and put one outside the square root. Sqrt(x^8) = x*sqrt(x^6)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the square root of 27 is 5.19

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you do that to your variables, and then break your 27 into its composite prime form, you'll be able to see everything you can take out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In simplifying, you don't usually calculate the square root, you just make it as small as possible. So if you have sqrt(8), you simplify it to 2 * sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you understand how simplifying works?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think i got it so the answer could be 3x^4y^2 square root 3y ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can i give you one more?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[63m ^{2}v ^{3} OVER 15^{6}v ^{5} \]63m^2v

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0forget about the bottom 63m

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not quite sure what you mean. Do you mean this? (63m^(2)*v^3)/(15^6*v^5)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am not sure either i just know i need to have my final answer be a binomial square.. hw haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But if you have something with a negative exponent like 1/n^(3), it's equal to n^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops wrong part soory!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i need to simplify the following and only use positive exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's the first step. Negative exponents are a pain to deal with. Then if you have something like this: n^4/n^2 you subtract the smaller from the larger. So n^2. Remember that if you wrote it out it'd be (n*n*n*n)/(n*n). If you crossed them out one by 1, you end up with n*n = n^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can we do the problem i put down? its for a test today... i have no clue haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoops, that wasn't for you

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Rewrite as:\[\sqrt{27x ^{8}y ^{5}}=\sqrt{9*3}\sqrt{x ^{8}}\sqrt{y ^{4}y}\] Now extract the square roots: \[3x ^{4}y ^{2}\sqrt{3y}\] I think that would be your answer. Use calculator to obtain square root of 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Omg, my computer is spazzing. That was for you, it was showing something from another window that confused me. And I can't read the problem you put down or I would.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got that thanks radar!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me with a diff prob? and no worries dwobwinkle ! i really appreciate it!

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Use to helpful, but have to review. You understand

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So I don't quite get it, what are you stuck on? I'm not able to interpret the question.
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