anonymous
  • anonymous
i need the steps in simplifying: square root of 27x^8y^5
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
You can break it up like this: sqrt(27)*sqrt(x^8)*sqrt(y^5)
anonymous
  • anonymous
If you have something raised to an exponent, such as x^8, you can subtract 2 from the exponent and put one outside the square root. Sqrt(x^8) = x*sqrt(x^6)
anonymous
  • anonymous
wait

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anonymous
  • anonymous
the square root of 27 is 5.19
anonymous
  • anonymous
If you do that to your variables, and then break your 27 into its composite prime form, you'll be able to see everything you can take out.
anonymous
  • anonymous
In simplifying, you don't usually calculate the square root, you just make it as small as possible. So if you have sqrt(8), you simplify it to 2 * sqrt(2)
anonymous
  • anonymous
Because 8 is 2*2*2
anonymous
  • anonymous
Do you understand how simplifying works?
anonymous
  • anonymous
also 3 *3 ^2 right?
anonymous
  • anonymous
i think i got it so the answer could be 3x^4y^2 square root 3y ??
anonymous
  • anonymous
That's right
anonymous
  • anonymous
can i give you one more?
anonymous
  • anonymous
Yea
anonymous
  • anonymous
\[63m ^{-2}v ^{3} OVER 15^{6}v ^{-5} \]63m^-2v
anonymous
  • anonymous
forget about the bottom 63m
anonymous
  • anonymous
I'm not quite sure what you mean. Do you mean this? (63m^(-2)*v^3)/(15^6*v^-5)?
anonymous
  • anonymous
i am not sure either i just know i need to have my final answer be a binomial square.. hw haha
anonymous
  • anonymous
But if you have something with a negative exponent like 1/n^(-3), it's equal to n^3
anonymous
  • anonymous
oops wrong part soory!
anonymous
  • anonymous
i need to simplify the following and only use positive exponents
anonymous
  • anonymous
That's the first step. Negative exponents are a pain to deal with. Then if you have something like this: n^4/n^2 you subtract the smaller from the larger. So n^2. Remember that if you wrote it out it'd be (n*n*n*n)/(n*n). If you crossed them out one by 1, you end up with n*n = n^2
anonymous
  • anonymous
can we do the problem i put down? its for a test today... i have no clue haha
anonymous
  • anonymous
whoops, that wasn't for you
radar
  • radar
Rewrite as:\[\sqrt{27x ^{8}y ^{5}}=\sqrt{9*3}\sqrt{x ^{8}}\sqrt{y ^{4}y}\] Now extract the square roots: \[3x ^{4}y ^{2}\sqrt{3y}\] I think that would be your answer. Use calculator to obtain square root of 3
anonymous
  • anonymous
Omg, my computer is spazzing. That was for you, it was showing something from another window that confused me. And I can't read the problem you put down or I would.
anonymous
  • anonymous
i got that thanks radar!
anonymous
  • anonymous
can you help me with a diff prob? and no worries dwobwinkle ! i really appreciate it!
radar
  • radar
Use to helpful, but have to review. You understand
anonymous
  • anonymous
huh
anonymous
  • anonymous
So I don't quite get it, what are you stuck on? I'm not able to interpret the question.

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