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anonymous

  • 5 years ago

i need the steps in simplifying: square root of 27x^8y^5

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  1. anonymous
    • 5 years ago
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    You can break it up like this: sqrt(27)*sqrt(x^8)*sqrt(y^5)

  2. anonymous
    • 5 years ago
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    If you have something raised to an exponent, such as x^8, you can subtract 2 from the exponent and put one outside the square root. Sqrt(x^8) = x*sqrt(x^6)

  3. anonymous
    • 5 years ago
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    wait

  4. anonymous
    • 5 years ago
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    the square root of 27 is 5.19

  5. anonymous
    • 5 years ago
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    If you do that to your variables, and then break your 27 into its composite prime form, you'll be able to see everything you can take out.

  6. anonymous
    • 5 years ago
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    In simplifying, you don't usually calculate the square root, you just make it as small as possible. So if you have sqrt(8), you simplify it to 2 * sqrt(2)

  7. anonymous
    • 5 years ago
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    Because 8 is 2*2*2

  8. anonymous
    • 5 years ago
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    Do you understand how simplifying works?

  9. anonymous
    • 5 years ago
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    also 3 *3 ^2 right?

  10. anonymous
    • 5 years ago
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    i think i got it so the answer could be 3x^4y^2 square root 3y ??

  11. anonymous
    • 5 years ago
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    That's right

  12. anonymous
    • 5 years ago
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    can i give you one more?

  13. anonymous
    • 5 years ago
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    Yea

  14. anonymous
    • 5 years ago
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    \[63m ^{-2}v ^{3} OVER 15^{6}v ^{-5} \]63m^-2v

  15. anonymous
    • 5 years ago
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    forget about the bottom 63m

  16. anonymous
    • 5 years ago
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    I'm not quite sure what you mean. Do you mean this? (63m^(-2)*v^3)/(15^6*v^-5)?

  17. anonymous
    • 5 years ago
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    i am not sure either i just know i need to have my final answer be a binomial square.. hw haha

  18. anonymous
    • 5 years ago
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    But if you have something with a negative exponent like 1/n^(-3), it's equal to n^3

  19. anonymous
    • 5 years ago
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    oops wrong part soory!

  20. anonymous
    • 5 years ago
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    i need to simplify the following and only use positive exponents

  21. anonymous
    • 5 years ago
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    That's the first step. Negative exponents are a pain to deal with. Then if you have something like this: n^4/n^2 you subtract the smaller from the larger. So n^2. Remember that if you wrote it out it'd be (n*n*n*n)/(n*n). If you crossed them out one by 1, you end up with n*n = n^2

  22. anonymous
    • 5 years ago
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    can we do the problem i put down? its for a test today... i have no clue haha

  23. anonymous
    • 5 years ago
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    whoops, that wasn't for you

  24. radar
    • 5 years ago
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    Rewrite as:\[\sqrt{27x ^{8}y ^{5}}=\sqrt{9*3}\sqrt{x ^{8}}\sqrt{y ^{4}y}\] Now extract the square roots: \[3x ^{4}y ^{2}\sqrt{3y}\] I think that would be your answer. Use calculator to obtain square root of 3

  25. anonymous
    • 5 years ago
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    Omg, my computer is spazzing. That was for you, it was showing something from another window that confused me. And I can't read the problem you put down or I would.

  26. anonymous
    • 5 years ago
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    i got that thanks radar!

  27. anonymous
    • 5 years ago
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    can you help me with a diff prob? and no worries dwobwinkle ! i really appreciate it!

  28. radar
    • 5 years ago
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    Use to helpful, but have to review. You understand

  29. anonymous
    • 5 years ago
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    huh

  30. anonymous
    • 5 years ago
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    So I don't quite get it, what are you stuck on? I'm not able to interpret the question.

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