discriminant:
COMPUTE THE DISCRIMINANT: (d =b^2 -4ac)
for the equation: (-1/6x^2) +3x -9 = 0

- anonymous

discriminant:
COMPUTE THE DISCRIMINANT: (d =b^2 -4ac)
for the equation: (-1/6x^2) +3x -9 = 0

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- anonymous

9-4(-1/6)(-9)=9-36/6=9-6=3

- anonymous

how do you solve can i get the steps :)

- anonymous

eitaK:
Check out the following:
http://answers.yahoo.com/question/index?qid=20080304153003AAUaVrd

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## More answers

- radar

Hey eitaK, I would multiply all terms by -6 to get:
\[x ^{2}-18x+54=0\]
then the discriminant would be \[-18^{2}-(4)(1)(54)=324-216=108\]

- anonymous

so technically you are getting rid of the fraction in the first step right?

- anonymous

and then how did you do the next step?

- radar

Yesm I believe twhitelsu is also correct. I am sort of confused here.

- radar

The next step was to square b (-18*-18) then subtract the 4ac or subtract (4*1*54)
The results did not equal the same as twhitelsu, and there is nothing wrong with the way it was done to get 3

- anonymous

ok but what happened to the x's?

- radar

I would stick the a, b, c, values of the original equation

- anonymous

ok so that is what i didn't and i go t -18^2- 4(1)(54)

- anonymous

sorry d= -18 not t.

- radar

The discriminant only deals with the coefficients of the variable not the variable itself. So there are no x in the discriminant.

- anonymous

ok

- anonymous

so then i went further and got-18^2 = -324 and then -4(1)(54) = -216

- anonymous

so then i woudl have D= -324 -216 correct?

- radar

Yes, but it doesn't come out as 3, as you would get if you had used the original equation for the values of a, b, c. I thought multiplying thru would simplify it, but it came out with a different discriminant. So apparently multipllying thru by-6 was not the right thing to do. I will think some more about this. I think you are on to the procedure to obtain discriminants.

- anonymous

i just used the equation that i was given. that i put abvoe :/

- radar

I just noticed that if I divides the results of 108 by 6 squared (36) it would be 3!!.

- anonymous

wait but where did you get 108

- anonymous

you've lost me,

- radar

The discriminant is that part of the quadratic formula that is within the radical and it is used to the following way: If it is greater than 0, their are two real solutions. If it equals zero there is one real solution (repeated).
If it is less than 0, there are no real solutions.

- radar

The -18 squared results in positive 324 (not the -324) when then combined with the -216 you get the 108 which is positive and means there are 2 real solutions.

- anonymous

ok... because it it positive?

- anonymous

and greater than 0 correct?

- radar

Yes

- anonymous

ok so then how do i get three as the discriminant?

- radar

Look at the work at the top of this page provided by twhitelsu.

- radar

She worked the probllem using the original equation working with the fractional value for a.

- anonymous

if i am going of yours, which makes a little more sense to me... how did you think and know to do that?

- radar

Did you follow her steps, see where b (3) was squared to become a 9

- anonymous

no i don't see where she got the 4 from.

- radar

I was trying to get rid of the 1/6 (I don't like fractions) lol the result were still positive but was not equal

- anonymous

i mean looking at hers. i see she has 4

- radar

the 4 was given in the discriminant equation: b^2-4ac, it is part of the 4ac. get it

- radar

you can see where she uses the a and c values being that a = -1/6 and c=-9

- anonymous

oh yes haha thanks.

- anonymous

but isn't the b supposed to be squared ? so 9^2

- radar

Look at your equation (-1/6)x^2+3x-9=0 the abc values for your equation are:
a=-1/6, b=3, c=-9 So b=3 and b squared if 9

- anonymous

gotcha! wow haha

- anonymous

THANKS FOR SPENDING ALL THAT TIME ON THIS PROB!

- radar

Here is form for a quadratic equation:
\[ax ^{2}+bx+c=0\]
Note that the abc represents numbers with a and b being the coefficients of variables and c is a constant.

- anonymous

wait whats that for?

- anonymous

oh i see.

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