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anonymous
 5 years ago
discriminant:
COMPUTE THE DISCRIMINANT: (d =b^2 4ac)
for the equation: (1/6x^2) +3x 9 = 0
anonymous
 5 years ago
discriminant: COMPUTE THE DISCRIMINANT: (d =b^2 4ac) for the equation: (1/6x^2) +3x 9 = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.094(1/6)(9)=936/6=96=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you solve can i get the steps :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0eitaK: Check out the following: http://answers.yahoo.com/question/index?qid=20080304153003AAUaVrd

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Hey eitaK, I would multiply all terms by 6 to get: \[x ^{2}18x+54=0\] then the discriminant would be \[18^{2}(4)(1)(54)=324216=108\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so technically you are getting rid of the fraction in the first step right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then how did you do the next step?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Yesm I believe twhitelsu is also correct. I am sort of confused here.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The next step was to square b (18*18) then subtract the 4ac or subtract (4*1*54) The results did not equal the same as twhitelsu, and there is nothing wrong with the way it was done to get 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok but what happened to the x's?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I would stick the a, b, c, values of the original equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so that is what i didn't and i go t 18^2 4(1)(54)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The discriminant only deals with the coefficients of the variable not the variable itself. So there are no x in the discriminant.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then i went further and got18^2 = 324 and then 4(1)(54) = 216

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then i woudl have D= 324 216 correct?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, but it doesn't come out as 3, as you would get if you had used the original equation for the values of a, b, c. I thought multiplying thru would simplify it, but it came out with a different discriminant. So apparently multipllying thru by6 was not the right thing to do. I will think some more about this. I think you are on to the procedure to obtain discriminants.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just used the equation that i was given. that i put abvoe :/

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I just noticed that if I divides the results of 108 by 6 squared (36) it would be 3!!.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait but where did you get 108

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The discriminant is that part of the quadratic formula that is within the radical and it is used to the following way: If it is greater than 0, their are two real solutions. If it equals zero there is one real solution (repeated). If it is less than 0, there are no real solutions.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The 18 squared results in positive 324 (not the 324) when then combined with the 216 you get the 108 which is positive and means there are 2 real solutions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok... because it it positive?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and greater than 0 correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so then how do i get three as the discriminant?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Look at the work at the top of this page provided by twhitelsu.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0She worked the probllem using the original equation working with the fractional value for a.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i am going of yours, which makes a little more sense to me... how did you think and know to do that?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Did you follow her steps, see where b (3) was squared to become a 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i don't see where she got the 4 from.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I was trying to get rid of the 1/6 (I don't like fractions) lol the result were still positive but was not equal

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean looking at hers. i see she has 4

radar
 5 years ago
Best ResponseYou've already chosen the best response.0the 4 was given in the discriminant equation: b^24ac, it is part of the 4ac. get it

radar
 5 years ago
Best ResponseYou've already chosen the best response.0you can see where she uses the a and c values being that a = 1/6 and c=9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but isn't the b supposed to be squared ? so 9^2

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Look at your equation (1/6)x^2+3x9=0 the abc values for your equation are: a=1/6, b=3, c=9 So b=3 and b squared if 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THANKS FOR SPENDING ALL THAT TIME ON THIS PROB!

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Here is form for a quadratic equation: \[ax ^{2}+bx+c=0\] Note that the abc represents numbers with a and b being the coefficients of variables and c is a constant.
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