anonymous
  • anonymous
discriminant: COMPUTE THE DISCRIMINANT: (d =b^2 -4ac) for the equation: (-1/6x^2) +3x -9 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
9-4(-1/6)(-9)=9-36/6=9-6=3
anonymous
  • anonymous
how do you solve can i get the steps :)
anonymous
  • anonymous
eitaK: Check out the following: http://answers.yahoo.com/question/index?qid=20080304153003AAUaVrd

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radar
  • radar
Hey eitaK, I would multiply all terms by -6 to get: \[x ^{2}-18x+54=0\] then the discriminant would be \[-18^{2}-(4)(1)(54)=324-216=108\]
anonymous
  • anonymous
so technically you are getting rid of the fraction in the first step right?
anonymous
  • anonymous
and then how did you do the next step?
radar
  • radar
Yesm I believe twhitelsu is also correct. I am sort of confused here.
radar
  • radar
The next step was to square b (-18*-18) then subtract the 4ac or subtract (4*1*54) The results did not equal the same as twhitelsu, and there is nothing wrong with the way it was done to get 3
anonymous
  • anonymous
ok but what happened to the x's?
radar
  • radar
I would stick the a, b, c, values of the original equation
anonymous
  • anonymous
ok so that is what i didn't and i go t -18^2- 4(1)(54)
anonymous
  • anonymous
sorry d= -18 not t.
radar
  • radar
The discriminant only deals with the coefficients of the variable not the variable itself. So there are no x in the discriminant.
anonymous
  • anonymous
ok
anonymous
  • anonymous
so then i went further and got-18^2 = -324 and then -4(1)(54) = -216
anonymous
  • anonymous
so then i woudl have D= -324 -216 correct?
radar
  • radar
Yes, but it doesn't come out as 3, as you would get if you had used the original equation for the values of a, b, c. I thought multiplying thru would simplify it, but it came out with a different discriminant. So apparently multipllying thru by-6 was not the right thing to do. I will think some more about this. I think you are on to the procedure to obtain discriminants.
anonymous
  • anonymous
i just used the equation that i was given. that i put abvoe :/
radar
  • radar
I just noticed that if I divides the results of 108 by 6 squared (36) it would be 3!!.
anonymous
  • anonymous
wait but where did you get 108
anonymous
  • anonymous
you've lost me,
radar
  • radar
The discriminant is that part of the quadratic formula that is within the radical and it is used to the following way: If it is greater than 0, their are two real solutions. If it equals zero there is one real solution (repeated). If it is less than 0, there are no real solutions.
radar
  • radar
The -18 squared results in positive 324 (not the -324) when then combined with the -216 you get the 108 which is positive and means there are 2 real solutions.
anonymous
  • anonymous
ok... because it it positive?
anonymous
  • anonymous
and greater than 0 correct?
radar
  • radar
Yes
anonymous
  • anonymous
ok so then how do i get three as the discriminant?
radar
  • radar
Look at the work at the top of this page provided by twhitelsu.
radar
  • radar
She worked the probllem using the original equation working with the fractional value for a.
anonymous
  • anonymous
if i am going of yours, which makes a little more sense to me... how did you think and know to do that?
radar
  • radar
Did you follow her steps, see where b (3) was squared to become a 9
anonymous
  • anonymous
no i don't see where she got the 4 from.
radar
  • radar
I was trying to get rid of the 1/6 (I don't like fractions) lol the result were still positive but was not equal
anonymous
  • anonymous
i mean looking at hers. i see she has 4
radar
  • radar
the 4 was given in the discriminant equation: b^2-4ac, it is part of the 4ac. get it
radar
  • radar
you can see where she uses the a and c values being that a = -1/6 and c=-9
anonymous
  • anonymous
oh yes haha thanks.
anonymous
  • anonymous
but isn't the b supposed to be squared ? so 9^2
radar
  • radar
Look at your equation (-1/6)x^2+3x-9=0 the abc values for your equation are: a=-1/6, b=3, c=-9 So b=3 and b squared if 9
anonymous
  • anonymous
gotcha! wow haha
anonymous
  • anonymous
THANKS FOR SPENDING ALL THAT TIME ON THIS PROB!
radar
  • radar
Here is form for a quadratic equation: \[ax ^{2}+bx+c=0\] Note that the abc represents numbers with a and b being the coefficients of variables and c is a constant.
anonymous
  • anonymous
wait whats that for?
anonymous
  • anonymous
oh i see.

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