A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 5 years ago
Solve the given equation and indicate the number of values of θ sach that 0≤θ<2π,that satisfy the iquation ;
2sin^2θsinθ1=0
anonymous
 5 years ago
Solve the given equation and indicate the number of values of θ sach that 0≤θ<2π,that satisfy the iquation ; 2sin^2θsinθ1=0

This Question is Closed

sgadi
 5 years ago
Best ResponseYou've already chosen the best response.0Take \[\sin\theta=x\] given equation \[2x^2x1=0\] solving above equation, we get x=0.5 or x=1 or we can say \[\sin\theta = 0.5\] or \[\sin\theta = 1\] so we can say the values of theta for which this is true is \[\theta = \frac{7\pi}{6},\frac{11\pi}{6},\frac{3\pi}{2}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.