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anonymous
 5 years ago
The curve whose equation is y=ax^3 + bx^2 + cx + d has a point of inflexion at (1,4), a turning point when x=2, and it passes through the point (3,7). Find the values of a, b, c and d.
anonymous
 5 years ago
The curve whose equation is y=ax^3 + bx^2 + cx + d has a point of inflexion at (1,4), a turning point when x=2, and it passes through the point (3,7). Find the values of a, b, c and d.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a=1 b=3 c=6 d=11 i think this is the answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would you please explain it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u need to differentiate y with respect to x. point of inflexion and turning point hav dy/dx=0 then u can manipulate the infos given to get b,c,d in term of a. so, u let a=1, u wil get the others.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think a=3/11 b=9/11 c=72/11 d=23/11

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the point of inflection implis the 2nd derivative is 0 not the first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0really? i thought because the tangent is zero, so it also implies the first derivative is zero. idk, i got it wrong. lol.. thanks twhite.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm...got it twhitelsu....thanks both of you... :)
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