anonymous
  • anonymous
A piece of land is shaped like a right triangle. Two people start at the right angle vertex of the triangle at the same time and walk the same speed along different legs of the triangle. If the area formed by the positions of the two ppl and their starting point (the right angle) is changing at 4m²/sec, then how fast are the ppl moving when they are 5m from the right angle?
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Think of this as a difference in areas problem: subtract one right triangle having two legs of 5m from another having two legs each 5m+dx, where dx is the rate at which the two individuals are travelling. This difference is equal to 4m^2/s: ((5+dx)^2)/2-(5^2)/2=4m^2/s (25+10*dx+dx^2-25)/2=4 (dx^2+10*dx)/2=4 dx^2+10*dx-8=0 Use the quadratic equation to solve for dx. Choose the positive answer.

Looking for something else?

Not the answer you are looking for? Search for more explanations.