anonymous
  • anonymous
please help me.....Mr. Hemley stands next to Illinois Centennial Monument at Logan Square in Chicago and casts a shadow that is 18 feet long. The shadow of the moniment is 204 feet long. If Mr. Hemley is 6 feet tall, how tall is the monument?
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
think is is 68.67 take 206 * 6=1236 then / that by 18
anonymous
  • anonymous
then round it
anonymous
  • anonymous
sorry...but I could not get you...please explain... :(

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
the answer is 68.67
anonymous
  • anonymous
but how could you get the answer?? ...I don't have a clue...please explain the process
anonymous
  • anonymous
68 is answer
anonymous
  • anonymous
The shadow of the moniment is 204 feet X Mr. Hemley is 6 feet tall, divide Logan Square in Chicago and casts a shadow that is 18 feet long the the answer you get by multiplying 204X6=1224/18=68
anonymous
  • anonymous
Way i remember doing it in math
anonymous
  • anonymous
ohh....thanks a lot... :)
anonymous
  • anonymous
was that the answer hopefuly could help you out
anonymous
  • anonymous
yeah...it helped me... :)
anonymous
  • anonymous
good glad to help

Looking for something else?

Not the answer you are looking for? Search for more explanations.