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anonymous
 5 years ago
solve the DE using exact method:
[sin(xy) + xycos(xy)]dx + [1 + x^2cos(xy)]dy=0
anonymous
 5 years ago
solve the DE using exact method: [sin(xy) + xycos(xy)]dx + [1 + x^2cos(xy)]dy=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know its exact I am getting stuck on doing the integral of Mdx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Integration by parts on the xycos(xy) doesnt work?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it works but then i keep ending up having to do it several times over and over so something is wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k so for the integration by parts i got xsin(xy) + cos(xy)/y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take the integral of [1 + x^2cos(xy)} instead

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats not what my rule says to do so i cant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know you can but my professor wont allow it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i didnt get the same answer for the integration by parts

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it would be the integral of x/ysin(xy)dx so i took out of the 1/y since its considered a constant so your left with xsin(xy)dx which requires IP again :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take the integral of [1 + x^2cos(xy) with respect to y then take the ppartial with respect to t  do you see what I am saying  you do it the same but opposite

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then i would be using the h(y) as h(x) since i am using the complete opposite formula now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i will figure it out that way...thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you will get \[y+ xsin(xy) \] this is the interal of [1 + x^2cos(xy) with respect to y then take the partial with respect to x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh exactly what i got....thankss

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont forget your constant \[\phi(x)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\phi(x)=0\] so the solution is y+xsin(xy)=c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yup i got that...thanks so much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is the good thing about exact form if you cant take the intergral of M try the integral of N

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh i am glad i know that now....only one more problem to go with this DE stuff and im done

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where do you go to school

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0college of saint elizabeth....small womans college in nj
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