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anonymous

  • 5 years ago

How do i find where the particle is at rest? The derivative is t(-1/5e^(-t/5))+e^(-t/5). I know to set it equal to zero but i cant figure out how to get the point

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  1. anonymous
    • 5 years ago
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    k so u r looking for solutions for t so ull have two parts one is where t = 0 and the second will be at e^(-t/5)=e^(-t/5)/5

  2. anonymous
    • 5 years ago
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    then take ln of both sides and u get ln(e^(-t/5)) = ln(5(e^(-t/5)))

  3. anonymous
    • 5 years ago
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    lol m solving it with u so going step by step hope it helps

  4. anonymous
    • 5 years ago
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    there is only one set of points. one (x,y). how do i set this up? ahhh okay i'm seeing it i think... keep it up i'm understanding you lol

  5. anonymous
    • 5 years ago
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    is it ln of 5 + ln of e^(-t/5)?

  6. anonymous
    • 5 years ago
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    yes

  7. anonymous
    • 5 years ago
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    so i have -t/5= ln 5 -t/5....

  8. anonymous
    • 5 years ago
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    yea no tht doesnt work double check the integral ... was there a substitution u used?

  9. anonymous
    • 5 years ago
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    sorry i mean the derivative

  10. anonymous
    • 5 years ago
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    no i actually already put the derivative into the webassign and it was right... now it wants when the particle is at rest

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