integral of (3x+1) dx? Upper limit =1. lower limit=0

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

integral of (3x+1) dx? Upper limit =1. lower limit=0

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\int\limits_{0}^{1} (3x+1)dx \] please explain. Im getting the answer 4. But im pretty sure its not correct...
(3x^2)/2 + x | (3(1)/2 + 1) -0 (because 3x0/2 +0 is obviously just 0) = 2 & 1/2
woops. sorry, the equation is actually :: \[ \int\limits_{0}^{1} (3x+1)^{2} \]. The answer is 7 but im getting 4

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

first, foil. (3x+1)^2= 9x^2+6x+1 dx = 3x^2+3x+x | (3+3+1) - 0 = 7
I expanded (3x +1)^2 to \[(3x+1) (3x+1) \] Then factored it. Then integrated it ..
okay, thank you!

Not the answer you are looking for?

Search for more explanations.

Ask your own question