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anonymous
 5 years ago
g(x) = x^4lnx what are the critical points of g?
anonymous
 5 years ago
g(x) = x^4lnx what are the critical points of g?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use Product rule to find derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find out where your derivative function hit zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take log on both side. log(y)=4ln(x)log(x) (1/y)dy/dx=(4/x)log(x)+(4/x)log(x) dy/dx=y[(8/x)log(x)] x^4lnx[(8/x)log(x)]=0 from here we find either x=0 or x=1 but x cant be 0 because domain of log(x) is greater then 0. so ans is 1
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