hi can someone help me please because i need help
well this is the problem: the sum of the digits of a two digit number is 12 times the tens digit. find the number.
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12 times the tens digit... So the sum of the digits has to be at least 12... I do not think this is the right question...
Do you mean three digits?
no just two digits thats what it says on my paper
Reason being: Even if the tens digit is 1, then the sum of the digits would have to be 12 - in other words, the ones digit would have to be 11... Impossible?
00, 01, 02, 03, 04, 05, 06, 07, 08, 09 all work...
That's the witty response, though.
!! Wrong, I didn't see it had to be equal to 12 times the value...
I don't think there is an answer.
really ok how about this one cuz i got stuck on it two: the sum of the digit of a two-digit number is 12.if 15 is added to the number,the result is 6 times the units digits. find the number
That seems plausible:
Let x = tens digit; y = units digit
Thus, 10x + y = the number
x + y = 12
10x + y + 15 = 6y
y = 2x + 3 (simplifying)
Plug that into x + y = 12
x + 2x + 3 = 12
3 x = 9
x = 3
y = 9