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anonymous

  • 5 years ago

what is the derivative of g(x) = cosh(ln(x))

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  1. anonymous
    • 5 years ago
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    Is that cos with the hyperbolic thing? or is that h * ln(x)?

  2. anonymous
    • 5 years ago
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    with the hyperbolic

  3. anonymous
    • 5 years ago
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    g'(x) = cosh(ln(x)) * 1/x

  4. anonymous
    • 5 years ago
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    Had to find out the derivative of cosh, but it's apparently just cosh.

  5. anonymous
    • 5 years ago
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    According to this: http://www.ucl.ac.uk/Mathematics/geomath/level2/hyper/hy4.html

  6. anonymous
    • 5 years ago
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    isnt it sinh?

  7. anonymous
    • 5 years ago
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    Crap, I keep looking at things wrong today... Yes, you're right: g'(x) = sinh(ln(x)) * 1/x

  8. anonymous
    • 5 years ago
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    I hope that's right, it's been a while since I last differentiated. :D

  9. anonymous
    • 5 years ago
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    Check that out on your calculator.

  10. anonymous
    • 5 years ago
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    thank u! ya it is right

  11. anonymous
    • 5 years ago
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    Woot :D Thanks for the +1

  12. anonymous
    • 5 years ago
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    haha np

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