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anonymous
 5 years ago
what is the derivative of g(x) = cosh(ln(x))
anonymous
 5 years ago
what is the derivative of g(x) = cosh(ln(x))

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is that cos with the hyperbolic thing? or is that h * ln(x)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0g'(x) = cosh(ln(x)) * 1/x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Had to find out the derivative of cosh, but it's apparently just cosh.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0According to this: http://www.ucl.ac.uk/Mathematics/geomath/level2/hyper/hy4.html

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Crap, I keep looking at things wrong today... Yes, you're right: g'(x) = sinh(ln(x)) * 1/x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I hope that's right, it's been a while since I last differentiated. :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Check that out on your calculator.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank u! ya it is right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Woot :D Thanks for the +1
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