anonymous
  • anonymous
what is the derivative of g(x) = cosh(ln(x))
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Is that cos with the hyperbolic thing? or is that h * ln(x)?
anonymous
  • anonymous
with the hyperbolic
anonymous
  • anonymous
g'(x) = cosh(ln(x)) * 1/x

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anonymous
  • anonymous
Had to find out the derivative of cosh, but it's apparently just cosh.
anonymous
  • anonymous
According to this: http://www.ucl.ac.uk/Mathematics/geomath/level2/hyper/hy4.html
anonymous
  • anonymous
isnt it sinh?
anonymous
  • anonymous
Crap, I keep looking at things wrong today... Yes, you're right: g'(x) = sinh(ln(x)) * 1/x
anonymous
  • anonymous
I hope that's right, it's been a while since I last differentiated. :D
anonymous
  • anonymous
Check that out on your calculator.
anonymous
  • anonymous
thank u! ya it is right
anonymous
  • anonymous
Woot :D Thanks for the +1
anonymous
  • anonymous
haha np

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