anonymous
  • anonymous
what are the critical points of 30(x-2)^2(x-4)^3
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Differentiate that! 30 * (2(x-2)*(x-4)^3 + 3(x-4)^2(x-2)) Set equal to zero... 30 * (2(x-2)*(x-4)^3 + 3(x-4)^2(x-2)) = 0 2(x-2)*(x-4)^3 + 3(x-4)^2(x-2)) = 0 x = 4 and x = 2
anonymous
  • anonymous
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anonymous
  • anonymous
sorry i meant the critical points of f'(x) = 30(x-2)^2(x-4)^3

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anonymous
  • anonymous
So of that function...? Then you gotta' differentiate it anyways and you'd get the same thing.

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