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anonymous

  • 5 years ago

find the discontinuity at f(x) = x-5/ x^2-4x-5

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  1. anonymous
    • 5 years ago
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    x=5

  2. anonymous
    • 5 years ago
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    how

  3. anonymous
    • 5 years ago
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    and x=-1 You need to factor out the bottom (x-5) (x+1) and then when either of these =0 there is discontinuity there for when x=5 and x=-1

  4. anonymous
    • 5 years ago
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    thx

  5. anonymous
    • 5 years ago
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    wat abt x^3-3x^2-9x

  6. anonymous
    • 5 years ago
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    there is none the closest you would get to discontinuity is =0 which is a value, there for no discontinuity unless there is more to this equation

  7. anonymous
    • 5 years ago
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    ok how?

  8. anonymous
    • 5 years ago
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    discontinuity involves getting an equation to divide by zero which gets you nowhere and the world end there for discontinuity

  9. anonymous
    • 5 years ago
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    ok thx wats ur name? ur really good

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