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- anonymous

If x² + y² = 5 and dx/dt = -3, then what is dy/dt when x = 1 and y = 2? Please show work

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- anonymous

If x² + y² = 5 and dx/dt = -3, then what is dy/dt when x = 1 and y = 2? Please show work

- katieb

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- amistre64

dx/dt tells us that the value of x is moving at a rate of -3 for every unit of time that passes. but that is a side not for the moment.
Lets get the derivative of the function implicitly since there is no (t) in the actual equation. Implicit deriviation is the same as normal except that you leave in your answers because they dont become (1).
(d/dt)(x^2) + (d/dt)(y^2) = (d/dt)(5)
(dx/dt)2x + (dy/dt)2y = (d5/dt)0
get (dy/dt) by itself thru algebra techniques:
(dy/dt) = [(d5/dt)0 - (dx/dt)2x] / 2y
fill in what we know:
(dy/dt) = [0 -(-3)(1)]/2
(dy/dt) = 3/2
And there we go :)

- anonymous

thanks alot i've been trying to solve that for a lil while now. makes sense, thank you. Are you good with word problems, too

- amistre64

lol....depends on the word problem :)

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- anonymous

right. well here you go. Boyle's law states that if the temperature of a gas remains constant, then PV = c, where P = pressure, V = volume and c is a constant. Given a quantity of gas at constant temperature, if V is decreasing at a rate of 14 in³/sec, at what rate is P increasing

- amistre64

Owww....that gives me a headache.. sorry, but I havent tried that one yet. It seems to be in every calc book, but I havent tried it yet. sorry :)
I can do the one with how much work does it take to pump out liguid from odd shaped containers :)

- anonymous

lol ok no problem

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