## anonymous 5 years ago how to test absolute convergence of series [(n+1)^n^2] ----------- (n)^n^2 exponents are n squared, just to be clear

you can consider this example in geometric series type: $\sum_{?}^{?}((n+1)^2/n^2)^n$ in geometric series if r^n is achieved and r=>1 then the serie is divergent. In here (n+1)^2/n^2 is always bigger than 1 so it is divergent bu arada Türksün demi lan:)