State the period, amplitude, max/min values, range, domain, horizontal phase shift and vertical displacement . y=-2sin[ 360 (t+1)/3)]

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

State the period, amplitude, max/min values, range, domain, horizontal phase shift and vertical displacement . y=-2sin[ 360 (t+1)/3)]

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

period:2pi/3 amplitude:-2 max:2 (-1<=sinx<=1) min:-2 range = [-2,2]
the (-2) tells us the amplitude; which means it fluctuates between 2 and -2. This is also the range since it cannot go outside of [-2,2] becuase the 2 is negative to begin with we know that the graph is flipped over from a normal sine graph; ie, goes down before it goes up. there is nothing added to the end of the equation to shift the y from its normal position so no vertical displacment. we can simply the innards by making (360/3) reduce to 120. which gives us the frequency; or how many cycles it has in 2pi. In this case, you want to fit 120 cycles into 2pi. since the (t) has been modified by a (+1) we have a horizontal shift. And the (+1) says that in order to (t) to get back to "0" we need to move it (+1). It makes sense in my head. So the horizontal shift is (-1). The sin graph normally has no restriction to its domain so neither does this; the domain is still (-inf,inf)
Max and min values would be 2 and -2 respectively. :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

period is wrong .it is pi/60...if you take 360 as a number and "6" if you take 360degree . so just make clear it only 360 or 360degree

Not the answer you are looking for?

Search for more explanations.

Ask your own question