## anonymous 5 years ago Rationalize the denominator square root 3 over sq.root26+5 does anyone know how to figure this out?

1. anonymous
2. amistre64

you have to multiply the top and bottom by sqrt(26+5) if that is in your denominator. What happens is the squareroots cancel and your left with 26+5 on the bottom. Actually, yo need to write the problem better cause it is kinda hard to tell what it is :)

3. anonymous

If this is your equation:$\sqrt{3}/\left( \sqrt{26} + 5 \right)$, then you need to multiply (numerator & denominator) by what's called the conjugate radical of the denominator: $\sqrt{26}-5$

4. amistre64

mrslange knows it :)