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anonymous
 5 years ago
Rationalize the denominator
square root 3 over sq.root26+5 does anyone know how to figure this out?
anonymous
 5 years ago
Rationalize the denominator square root 3 over sq.root26+5 does anyone know how to figure this out?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Check out: http://www.helpalgebra.com/articles/rationalizedenominator.htm

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you have to multiply the top and bottom by sqrt(26+5) if that is in your denominator. What happens is the squareroots cancel and your left with 26+5 on the bottom. Actually, yo need to write the problem better cause it is kinda hard to tell what it is :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If this is your equation:\[\sqrt{3}/\left( \sqrt{26} + 5 \right)\], then you need to multiply (numerator & denominator) by what's called the conjugate radical of the denominator: \[\sqrt{26}5\]
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