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anonymous

  • 5 years ago

Find all solutions of the equation. (Enter each answer in the form θ + 2πk, 0 ≤ θ < 2π. If there are any unused answer boxes, enter NONE in the last boxes.) 2cos^2(x)-cos(x)-1=0

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  1. anonymous
    • 5 years ago
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    You can factor this expression.

  2. anonymous
    • 5 years ago
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    i factored it to get (2cos(x) + 1)(cos(x) - 1) = 0

  3. anonymous
    • 5 years ago
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    \[(2\cos(x)+1)(\cos(x)-1)=0\]

  4. anonymous
    • 5 years ago
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    now set each factor equal to zero and solve for x

  5. anonymous
    • 5 years ago
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    Cos(x)= -1/2 and Cos(x)= 1

  6. anonymous
    • 5 years ago
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    yes, but now you need to express all possible angles for which those ratios are correct

  7. anonymous
    • 5 years ago
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    2pi/3, 4pi/3 and 2pi?

  8. anonymous
    • 5 years ago
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    plus 2pik on all of them

  9. anonymous
    • 5 years ago
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    yep

  10. anonymous
    • 5 years ago
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    thank you!

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spraguer (Moderator)
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