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3times3 is 9 which doesnt factor into 7.... so quadratic it :)

after using the quadratic formula, how do you complete the problem?

my textbook says to find the nearest degree.. x = sin of theta

not really :/

ok, let me see.

where do you get 49?

oh. it's b^2? no wonder i never got any solution out of that. thank you very much!
+5

we got numbers for our x now; (7/6 (+-) sqrt(85)/6) if I did it correctly right?

umm.. i'm still solving it. i got the b^2 correct

my calculator says -49 instead of 49. so weird～

i think it was supposed to be 7 not -7

all it changes in the end is the sign of (7/6) to (-7/6) which may or may not be an issue

got it.
\[x=7\pm \sqrt{49+36} \div 6\]

good :) you ready to learn about sin inverse? its symbol is (sin^-1)

i know sin^-1 but i'm stuck in where should i go next.

lets walk it thru. It asks us to find sin(t) = x right?

sin \[\theta\]

theta is simply a name, I will make it simpler and just name it "t" do you think I can do that?

yea, sure. :)

lol...good, mathmaticians like to rename things all the time, makes them feel important :)

XD

wait. i'm confused here. do i continue with the quad. formula?

so i continue with this:\[3\sin^2\theta-7\sin \theta-3=0\]

aha!!! you were holding back vital information...hmmm

opps.. am i in trouble?

nah....just makes the problem more understandable now :)

XD. so how do i continue?

[7-sqrt(85)]/6 = -0.3699 which IS between -1 and 1 so it is a good value of x.

is there anyway to verify the answer?

i got the same answer as you. -0.3699240762

either were both geniuses or were both idiots...take your pick :)

GENIUS! :D

yay!!!

does any of that make sense to you?

somewhat, let me think over~

i think i got it, thanks for helping me though(: