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anonymous
 5 years ago
I NEED MAJOR HELP IM TRYING TO SOLVE EQUATIONS WITH EXPONENTS
(X+1)^3/2=64
anonymous
 5 years ago
I NEED MAJOR HELP IM TRYING TO SOLVE EQUATIONS WITH EXPONENTS (X+1)^3/2=64

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^3 + 1 /2 = 64 Find the greatest common denominator, so 2 x 64 = 128 x^3 + 1 = 128 ( cancel out denominators) x^3 = 127

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I may be wrong however

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, you are wrong.. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply both sides by 2. (x+1)^3 = 128. to get rid of the exponents, take the cube root of both sides. x+1 = cbrt (128). x = cbrt(128)  1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's assuming the 2 is not part of the exponent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ahh nicely done man I'm only 15 so forgot to cube root :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem i'm older than that be careful about giving out help if you're not sure though :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0SO WHATS THE ANSWER A)15B)511C)17D)21

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we should verify what the equation actually is because the way it is is confusing.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(X+1)^(3/2)=64 ? or [(X+1)^3]/2=64

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats what you had typed before, and it is ambiguous. Pick one of the ones I offered please.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ok... (X+1)^(3/2)=64 ln((x+1)^(3/2)) = ln(64) (3/2) ln(x+1) = ln(64) log2(x+1) = (2/3) log2(64) log2(x+1) = (2/3) (6) log2(x+1) = 4 x+1 = 2^4 x+1 = 16 x = 15 if I did it all right :)
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