anonymous
  • anonymous
I NEED MAJOR HELP IM TRYING TO SOLVE EQUATIONS WITH EXPONENTS (X+1)^3/2=64
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
hey
anonymous
  • anonymous
x^3 + 1 /2 = 64 Find the greatest common denominator, so 2 x 64 = 128 x^3 + 1 = 128 ( cancel out denominators) x^3 = 127
anonymous
  • anonymous
I may be wrong however

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anonymous
  • anonymous
yeah, you are wrong.. :)
anonymous
  • anonymous
lol thought so
anonymous
  • anonymous
multiply both sides by 2. (x+1)^3 = 128. to get rid of the exponents, take the cube root of both sides. x+1 = cbrt (128). x = cbrt(128) - 1
anonymous
  • anonymous
that's assuming the 2 is not part of the exponent
anonymous
  • anonymous
Ahh nicely done man I'm only 15 so forgot to cube root :P
anonymous
  • anonymous
no problem i'm older than that be careful about giving out help if you're not sure though :)
anonymous
  • anonymous
SO WHATS THE ANSWER A)15B)511C)17D)21
amistre64
  • amistre64
we should verify what the equation actually is because the way it is is confusing.
amistre64
  • amistre64
(X+1)^(3/2)=64 ? or [(X+1)^3]/2=64
anonymous
  • anonymous
(X+1)^2/3=64
amistre64
  • amistre64
thats what you had typed before, and it is ambiguous. Pick one of the ones I offered please.
anonymous
  • anonymous
THE FIRST
amistre64
  • amistre64
ok... (X+1)^(3/2)=64 ln((x+1)^(3/2)) = ln(64) (3/2) ln(x+1) = ln(64) log2(x+1) = (2/3) log2(64) log2(x+1) = (2/3) (6) log2(x+1) = 4 x+1 = 2^4 x+1 = 16 x = 15 if I did it all right :)
anonymous
  • anonymous
THANKS SO MUCH

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