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anonymous
 5 years ago
How does sin(t)/(1cos(t)) simplify to cos(t)/sin(t)?
anonymous
 5 years ago
How does sin(t)/(1cos(t)) simplify to cos(t)/sin(t)?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure that's the exact question as written?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It doesn't. Pick t=5 and you'll see it doesn't work.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well it's that I'm looking at a solution my teacher wrote. He was showing how a cycloid had infinitely sharp cusps by finding the limit of the derivative of the parametric formulas given. So he was trying first to find the limit of sin(t)/(1cos(t)) and he jumped to trying to find the limit of cos(t)/sin(t) because apparently, they're equal.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Look at #5. http://people.sfcollege.edu/bruce.teague/pdf/2312%20W11/2312_MG5_solutions_W11.pdf This link should work.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now what am I gonna do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Calm down...I'll have a look.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, he's used L'Hopital's rule...do you know about that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe. I might have forgotten.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you have indeterminate forms for the limit (numerator and denominator each go to something like 0/0 or infinity/infinity), the limit of the original ratio is equal to the limit ratio of the derivatives of the numerator and denominator.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Take the derivative of the numerator of sin(t) and you get cos(t), and the derivative of 1cost(t) is sin(t).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh! It's all coming back now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK. That makes sense. Thank you soooooo much.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Fan me then! :) I want to reach superstar!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How does one fan someone else?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{t \rightarrow 0} \frac{sin(t)}{1\cos(t)}= \frac{0}{11}=\frac{0}{0}\] lokisan is right, this is an indeterminate and using L'hopital would give you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there should be a linktype thing next to my name..."Become a fan"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not seeing it. I'm looking.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's in the thread window...little 'thumbs up' icon. There's one next to your own name too.
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