can someone explain the quadratic formula to me please

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can someone explain the quadratic formula to me please

Mathematics
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Yes, the quadratic formula is what you end up with when you "complete the square". "Completing the square" is proof that the quad formula works. Anything specific you wanna know?
\[5x ^{2} +3x+ 7= 0\]how would i do it with the equation
Just curious, do you know what "quadratic" means? at first I thought it had to do with "4" ... but it is just a fancy name for a squared function like x^2.

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yea im learning about it in math but hes confusing me
Lets start with the basics and then I will get to your equation ok? Tell me what the quad formula is so I know you have a grasp on it.
how to find continuity of function of 2 vars??
Hi think, that doesnt ring a bell. sorry... Are the variables independant or does one depend on the other?
\[-b \sqrt{b ^{2}- 4 (bc} \div 2 (a) \]
its like, lim(x,y)->(1,2){x/sqrt[2x+y]}}
that just confused me
david, for your question, a quadratic equation is which has x power 2, and what you mentioned now is the 'discriminant'
@think: that doesnt look familiar to me. David; it looks like you know the formula; but might have troubles with formatting it with the website... But yes, you are basically right. lets define a, b, and c. a = the first term; b= the middle term, and c= the last term. Does that make sense?
that is a way to find out the roots
yeah after that im lost and i asked him to help me and he confused me even more
@amistre, its like limit of (x,y)->(1,2) with the function as x/ sqrt(2x + y)
lets re-write the top like this: -(middle) +-sqrt(middle^2 - (4)(first)(last)) How does that look to you?
that actually makes sense
@think, I would assume that any values of (x,y) that make the bottom a zero have something to do with it. But I am just not sure.
@David: good then lets call the bottom part of the formula: 2(first) does that help?
yeah
So what was your original equation again and lets see if we can work it out now.
i think twas 5x^2 + 3x + 7 =0
right?
yea
@thnk: what happens when you plug in (1,2) into the equation, does it get a number or an indeterminiate value?
thinker wat grade r u in
5x^2 + 3x + 7 first = (+5) ; middle = (+3); and last = (+7) top of quad form: -3 +- sqrt(3^2 -(4)(5)(7)) ------------------------ bottom part: 2(5) What do we get?
10
sry..it freezed again....i get the answer as 1/2
10 is the bottom of it; but what is the top part of the quad form equal; remember it is just a big fraction looking monstorcity :)
then as (x,y) approaches (1,2) that was the original right? then the equation approaches (1/2) if you plugged it in correctly :)
-3 +- sqrt 9 -140
good; does (-3 + sqrt(-131)) / 10 have any meaning to you? In other words can we have any real values for sqrt(-131)? Let me ask it this way.... what number when multiplied by itself will give you a "negative" answer?+
yeah...so what 's the continuity?
no it has no real solution i think
@think; rationalize the denominator and see if that helps :)
@David; very good, that is the correct answer, there are no "real" values of 'x'. Tell me, what does it mean to be a "real" value?
when a number has a square root??
@ david, good enough answer :) Have you dealt with "imaginary" numbers yet?
no
@amistre, have u anytime seen "Thomas' Calculus" text?
oh r u tlking about the imaginery 1 in front of x
@david, no..imaginary numbers are those which do not exist..like sqrt of a negative number etc
oh
@think; doesnt ring a bell :) @david; lol....good attempt at, but no. the "1" infront of an x is actually there, we just dont write it because it is
1(x) = x the only imaginary number there is, is called "i" and we simply define it as : i = sqrt(-1) it is the only way in which we can solve the squareroots of negative numbers.
ohh..was just a try..not an "algebra" person
@amistre, have u anytime seen "Thomas' Calculus" text??
Thomas Calculus text doesnt sound familiar to me...
ohh..:(..its a huge book..which i have to study from..
I have a few good books in the college library (public libraries here are a joke) that I use. Some are more helpful than others at times.
How did we do with your 1/sqrt(2x+y) question so far?
this function is continous only when the denominator,i.e x,y\[\neq\]0
And do we know if y is a function of x; or if x is a function of y; or if they are independant variables?
there's nothing mentioned...its just that we ve to find the points of continuity/discontinuity
So when (2x+y) = 0 there is a Vertical Asymptote right? When y = -2x and when x = -y/2
vertical asymptote? what is that?
there are a few types of discontinuities available to us: the "hole" is a line is called a jump disconiuity becasue the line will forever get close to it and never touch it. the "vertical" asymptote is a value for "x" that the graph will forever slide right up next to but never touch so instead of a jump across a hole, we get a neverending curve that approaches "x"
sry..didn't get that:(
Holes occur when you can cross out like factors top to bottom. VAs occur when whats left after crossing out makes the bottom equal to "0"
@amistres64 may u pls help me
that was odd... :) kabelo, what is your question? and maybe I can help
@think: think of the graph for f(x) = x^2; and restrict the domain to x<4 and x>4. there is no value for f(x) at x=4; it just makes a hole.
i know is bascially algebra
kab: basic algebra is good :) what is your question?
the veranda is covered with tiles(30cm times 30cm) in 5 black and4 white tiles,how many black tiles are used to cover the veranda floor if that pattern is continued.the area is 4,2m
Kab: Ill go over to that posting , this ones getting rather long ok?
can i join?
yip pls do ,yes u can.
what was the question there? unable to find it:(
the veranda is covered with tiles(30cm times 30cm) in 5 black and4 white tiles,how many black tiles are used to cover the veranda floor if that pattern is continued.the area is 4,2m

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