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anonymous
 5 years ago
can someone explain the quadratic formula to me please
anonymous
 5 years ago
can someone explain the quadratic formula to me please

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, the quadratic formula is what you end up with when you "complete the square". "Completing the square" is proof that the quad formula works. Anything specific you wanna know?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[5x ^{2} +3x+ 7= 0\]how would i do it with the equation

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Just curious, do you know what "quadratic" means? at first I thought it had to do with "4" ... but it is just a fancy name for a squared function like x^2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea im learning about it in math but hes confusing me

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Lets start with the basics and then I will get to your equation ok? Tell me what the quad formula is so I know you have a grasp on it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how to find continuity of function of 2 vars??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Hi think, that doesnt ring a bell. sorry... Are the variables independant or does one depend on the other?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[b \sqrt{b ^{2} 4 (bc} \div 2 (a) \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its like, lim(x,y)>(1,2){x/sqrt[2x+y]}}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that just confused me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0david, for your question, a quadratic equation is which has x power 2, and what you mentioned now is the 'discriminant'

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@think: that doesnt look familiar to me. David; it looks like you know the formula; but might have troubles with formatting it with the website... But yes, you are basically right. lets define a, b, and c. a = the first term; b= the middle term, and c= the last term. Does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is a way to find out the roots

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah after that im lost and i asked him to help me and he confused me even more

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre, its like limit of (x,y)>(1,2) with the function as x/ sqrt(2x + y)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets rewrite the top like this: (middle) +sqrt(middle^2  (4)(first)(last)) How does that look to you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that actually makes sense

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@think, I would assume that any values of (x,y) that make the bottom a zero have something to do with it. But I am just not sure.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@David: good then lets call the bottom part of the formula: 2(first) does that help?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0So what was your original equation again and lets see if we can work it out now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think twas 5x^2 + 3x + 7 =0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@thnk: what happens when you plug in (1,2) into the equation, does it get a number or an indeterminiate value?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thinker wat grade r u in

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05x^2 + 3x + 7 first = (+5) ; middle = (+3); and last = (+7) top of quad form: 3 + sqrt(3^2 (4)(5)(7))  bottom part: 2(5) What do we get?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry..it freezed again....i get the answer as 1/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.010 is the bottom of it; but what is the top part of the quad form equal; remember it is just a big fraction looking monstorcity :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then as (x,y) approaches (1,2) that was the original right? then the equation approaches (1/2) if you plugged it in correctly :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0good; does (3 + sqrt(131)) / 10 have any meaning to you? In other words can we have any real values for sqrt(131)? Let me ask it this way.... what number when multiplied by itself will give you a "negative" answer?+

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah...so what 's the continuity?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no it has no real solution i think

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@think; rationalize the denominator and see if that helps :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@David; very good, that is the correct answer, there are no "real" values of 'x'. Tell me, what does it mean to be a "real" value?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when a number has a square root??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@ david, good enough answer :) Have you dealt with "imaginary" numbers yet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre, have u anytime seen "Thomas' Calculus" text?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh r u tlking about the imaginery 1 in front of x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@david, no..imaginary numbers are those which do not exist..like sqrt of a negative number etc

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@think; doesnt ring a bell :) @david; lol....good attempt at, but no. the "1" infront of an x is actually there, we just dont write it because it is

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01(x) = x the only imaginary number there is, is called "i" and we simply define it as : i = sqrt(1) it is the only way in which we can solve the squareroots of negative numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh..was just a try..not an "algebra" person

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre, have u anytime seen "Thomas' Calculus" text??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Thomas Calculus text doesnt sound familiar to me...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh..:(..its a huge book..which i have to study from..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I have a few good books in the college library (public libraries here are a joke) that I use. Some are more helpful than others at times.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0How did we do with your 1/sqrt(2x+y) question so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this function is continous only when the denominator,i.e x,y\[\neq\]0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0And do we know if y is a function of x; or if x is a function of y; or if they are independant variables?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there's nothing mentioned...its just that we ve to find the points of continuity/discontinuity

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0So when (2x+y) = 0 there is a Vertical Asymptote right? When y = 2x and when x = y/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0vertical asymptote? what is that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there are a few types of discontinuities available to us: the "hole" is a line is called a jump disconiuity becasue the line will forever get close to it and never touch it. the "vertical" asymptote is a value for "x" that the graph will forever slide right up next to but never touch so instead of a jump across a hole, we get a neverending curve that approaches "x"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry..didn't get that:(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Holes occur when you can cross out like factors top to bottom. VAs occur when whats left after crossing out makes the bottom equal to "0"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistres64 may u pls help me

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that was odd... :) kabelo, what is your question? and maybe I can help

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0@think: think of the graph for f(x) = x^2; and restrict the domain to x<4 and x>4. there is no value for f(x) at x=4; it just makes a hole.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know is bascially algebra

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0kab: basic algebra is good :) what is your question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the veranda is covered with tiles(30cm times 30cm) in 5 black and4 white tiles,how many black tiles are used to cover the veranda floor if that pattern is continued.the area is 4,2m

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Kab: Ill go over to that posting , this ones getting rather long ok?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yip pls do ,yes u can.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what was the question there? unable to find it:(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the veranda is covered with tiles(30cm times 30cm) in 5 black and4 white tiles,how many black tiles are used to cover the veranda floor if that pattern is continued.the area is 4,2m
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