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\[5x ^{2} +3x+ 7= 0\]how would i do it with the equation

yea im learning about it in math but hes confusing me

how to find continuity of function of 2 vars??

\[-b \sqrt{b ^{2}- 4 (bc} \div 2 (a) \]

its like, lim(x,y)->(1,2){x/sqrt[2x+y]}}

that just confused me

that is a way to find out the roots

yeah after that im lost and i asked him to help me and he confused me even more

that actually makes sense

yeah

So what was your original equation again and lets see if we can work it out now.

i think twas 5x^2 + 3x + 7 =0

right?

yea

thinker wat grade r u in

10

sry..it freezed again....i get the answer as 1/2

-3 +- sqrt 9 -140

yeah...so what 's the continuity?

no it has no real solution i think

when a number has a square root??

@ david, good enough answer :) Have you dealt with "imaginary" numbers yet?

no

oh r u tlking about the imaginery 1 in front of x

oh

ohh..was just a try..not an "algebra" person

Thomas Calculus text doesnt sound familiar to me...

ohh..:(..its a huge book..which i have to study from..

How did we do with your 1/sqrt(2x+y) question so far?

this function is continous only when the denominator,i.e x,y\[\neq\]0

there's nothing mentioned...its just that we ve to find the points of continuity/discontinuity

So when (2x+y) = 0 there is a Vertical Asymptote right?
When y = -2x
and when x = -y/2

vertical asymptote? what is that?

sry..didn't get that:(

@amistres64 may u pls help me

that was odd... :) kabelo, what is your question? and maybe I can help

i know is bascially algebra

kab: basic algebra is good :) what is your question?

Kab: Ill go over to that posting , this ones getting rather long ok?

can i join?

yip pls do ,yes u can.

what was the question there? unable to find it:(