Sabrina has $3.10 in nickels and dimes. If she has 52 coins in all, how many of each does he have?
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Here are the facts: 52 coins consisting of dimes and nickels.
They add up to $3.10 Here is a way to solve a problem like this.
Let x equal the number of dimes. (This is an arbitrary decision on my part)
Since x equals the number of dimes how many nickels does she have?
The total number of coins are 52. So the number of nickels are 52-x
What do we have so far?
x=number of dimes
52-x=number of nickels. Please note this is the number of dimes and nickels not their value. The value amount is important we know the value of 1 dime or nickel.
simply multiply the value by the number of coins. this will get us the following
.10 x is the value of dimes
.05*(52-x) is the value of the nickels. Their combined total is $3.10
.10x + .05(52-x)=$3.10
.05x=3.10-2.6=.5 or .05x=.5 number of dimes would be .5/.05=10 dimes.
52-10 gives the number of nickels, or 42 nickels. Lets check: Total number of coins is 10 + 42 = 52 coins. Check Now the amount of money, does it check?
10 dimes is $1.00, 42 nickels is $2.10, add them and the sum is $3.10 checks
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