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anonymous

  • 5 years ago

2cos theta = sec theta.. what are they asking me to find?

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  1. anonymous
    • 5 years ago
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    \[\theta\]

  2. anonymous
    • 5 years ago
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    \[2\cos\theta=\sec\theta\]

  3. anonymous
    • 5 years ago
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    the exact values of the degree?

  4. anonymous
    • 5 years ago
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    i would think so

  5. anonymous
    • 5 years ago
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    on what interval?

  6. anonymous
    • 5 years ago
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    0 degree to 360 degree

  7. anonymous
    • 5 years ago
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    \[2\cos{\theta}=\sec{\theta} \rightarrow 2\cos{\theta}=\frac{1}{\cos{\theta}}\]then\[2\cos^2{\theta}=1\]

  8. anonymous
    • 5 years ago
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    \[\cos{\theta}={\pm}\frac{1}{\sqrt{2}}\]

  9. anonymous
    • 5 years ago
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    Find all those angles theta that satisfy this.

  10. anonymous
    • 5 years ago
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    θ = 45, 215, 135, 225

  11. anonymous
    • 5 years ago
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    itsmesowat.. how'd you get the answers?

  12. anonymous
    • 5 years ago
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    use your unit circle or other favorite method to get special angle values for consine...

  13. anonymous
    • 5 years ago
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    use the calculator do [2nd] [cos] of the fraction 1/rad(2)

  14. anonymous
    • 5 years ago
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    Draw a right-angled triangle with sides 1, 1 and hypotenuse sqrt(2). cos(theta)=1/sqrt(2) when theta = 45 degrees. In the second quadrant, 180-45 = 135 degrees, in the third, 180+45 degrees = 225 and in the fourth, 360-45 = 315 degrees/

  15. anonymous
    • 5 years ago
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    gotcha.

  16. anonymous
    • 5 years ago
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    you got everything lokisan said? you are a genius!!~~~~

  17. anonymous
    • 5 years ago
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    lol tyler.. where'd you get 215 degrees?

  18. anonymous
    • 5 years ago
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    215 is typo, should be 225, which is 180+45, reference angle of 135

  19. anonymous
    • 5 years ago
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    gotcha.

  20. anonymous
    • 5 years ago
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    sorry i suck at typing out math... they should introduce the white board on this haha

  21. anonymous
    • 5 years ago
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    lmao. XD

  22. anonymous
    • 5 years ago
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    they have these equation thingys. it's built from mathjax

  23. anonymous
    • 5 years ago
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    wait. how'd you get 1/sqrt of 2?

  24. anonymous
    • 5 years ago
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    2cos^2(theta)=1. Divide both sides by 2, then take the sqrt of both sides.

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spraguer (Moderator)
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