anonymous
  • anonymous
Find three consecutive integers such that the sum of twice the smallest and three times the largest is 126.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
24 25 26
anonymous
  • anonymous
you have been given that 2a+3(a+2)=126 so, simply solve for a: - expand the brackets, 2a+3a+6=126 collect like terms; 5a=120 divide by 5; a=24 this gives the first number in the sequence so then a+1=25 and a+2=26
anonymous
  • anonymous
Thanks!

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