solve the DE using the exact method: dy/dx=-[(y^3+4e^xy)/(2e^x+3y^2)]

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solve the DE using the exact method: dy/dx=-[(y^3+4e^xy)/(2e^x+3y^2)]

Mathematics
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i know how to do the exact mthod just looking for help getting them equal to work
what do you mean getting them equal?
in the form of Mdx + Ndy =0

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Move everything to left hand side by multiplying and then adding so the RHS is equal to 0. Then multiply each term by dx
multiply each term by dx?
Yeah, you have to pretend dy/dx is a fraction and multiple each term by dx so you get dy on one term and dx on the other
cant i do cross multiplication with the original equation?

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