anonymous
  • anonymous
A bag contains 7 blue counters, 5 green counters, and 3 pink counters. The probability of randomly drawing a green counter is 1/3. What is the probability of not drawing a green counter
Mathematics
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anonymous
  • anonymous
A bag contains 7 blue counters, 5 green counters, and 3 pink counters. The probability of randomly drawing a green counter is 1/3. What is the probability of not drawing a green counter
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
help please :0
anonymous
  • anonymous
probability of not drawing a green counter = probability of drawing blue counters + pink counters
anonymous
  • anonymous
or 1 - probability of drawing a green counter

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anonymous
  • anonymous
2/3 is the answer
anonymous
  • anonymous
so 1 is actually the sum of all probability (in case u need to write it down .... probability of blue + prob. of pink + prob. of green)
anonymous
  • anonymous
\[probability \left( pink \right)+prob.\left( blue \right)+prob.\left( green \right)=your answer\]

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