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anonymous
 5 years ago
How do you use the Method of Undetermined Coefficients when the right side of the equation (x(t)) is not a given function. AKA  y(t) + 5y'(t) = x(t)
anonymous
 5 years ago
How do you use the Method of Undetermined Coefficients when the right side of the equation (x(t)) is not a given function. AKA  y(t) + 5y'(t) = x(t)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to take the characteristic equation and set that equal to zero. Once and ONLY once you do that you can solve for the rest of the equation. I also recommend using the LaPLACE method for help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Isn't the total answer the general solution + the particular solution? So that the general solution is the answer as if it were homogenous, but how do you find the particular solution?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The characteristic equation would be 1+ 5r = 0, r = 1/5. So I have \[y = ce ^{1/5t}\] however wolfram alpha shows the answer as \[y = ce ^{1/5t} + x  5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Did you look at the hints?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry what hints? http://www.wolframalpha.com/input/?i=y+%2B+5y%27+%3D+x
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