anonymous
  • anonymous
Kim's coffee shop sells a cup of tea for $1.05, a cup of coffee for $1.35, and a cup of hot chocolate for $2.25 . One busy day, 20 more cups of coffee than of hot chocolate were sold, and 30 more cups of coffee than tea, for a total of 202.50 for all three hot drinks. How many cups of each drink were sold?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
T=1.05; C=1.35; Hc=2.25. C = Hc+20 ; C=T+30. Hc + 20 = T+30 sooo... Hc = T +30-20 Hc = T + 10 this is what I got so far :)
amistre64
  • amistre64
(T+30)(1.35) + (T+10)(2.25) + T(1.05) = 202.50 If I did it right :)
amistre64
  • amistre64
1.35T + 40.5 + 2.25T +22.5 + 1.05T = 202.50

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amistre64
  • amistre64
T(1.35 +2.25+1.05) +63 = 202.50 T(4.65) = 202.50 -63 T = 139.5/4.65 T = 30. There were 30 teas sold.
amistre64
  • amistre64
C=T+30 and Hc = T+10 60 coffees sold; and 40 hot chocolates sold.
amistre64
  • amistre64
Am I right?
anonymous
  • anonymous
Thank you :)
anonymous
  • anonymous
yur a genius
amistre64
  • amistre64
awww.... you only saying that cause its true :)
anonymous
  • anonymous
yah :) thnks again
anonymous
  • anonymous
kso , I'm doing the same question , but I don't get how you got " 1.35T + 40.5 + 2.25T +22.5 + 1.05T = 202.50" ?

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