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anonymous

  • 5 years ago

hello I am trying to understand why the limit of as x->0 from the right for (lnx)/(sinx) is -infinity

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  1. anonymous
    • 5 years ago
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    use l'hosptitals rule

  2. anonymous
    • 5 years ago
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    I am I just dont undesrtand how you get that answer

  3. anonymous
    • 5 years ago
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    the top gives me 1/x and the bottom cos x which is still undetermined at the top

  4. anonymous
    • 5 years ago
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    that equals 1/xcosx

  5. anonymous
    • 5 years ago
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    i get that part but how does that end up being negative infinity

  6. amistre64
    • 5 years ago
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    as ln(x) approaches 0 we go to negative infinity as sin(x) approaches 0 we go to 1

  7. amistre64
    • 5 years ago
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    the graph of ln(x) as it approaches 0 drops down and down and down and never touches 0....it goes to -inf.

  8. anonymous
    • 5 years ago
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    got it thank you

  9. amistre64
    • 5 years ago
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    yay!! :)

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spraguer (Moderator)
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