anonymous
  • anonymous
A 20 ft diagonal brace on a bridge connects a support of the center of the bridge to a side support on the bridge.The horizontal distance that it spans is 4 ft longer than that the height reaches on the side of the bridge.Find the horizontal and vertical distances spanned by this brace.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
dude, I just figured out im am idiot :) 9 * 7 = 63 and 9 =2+7....
anonymous
  • anonymous
what is this
amistre64
  • amistre64
the last question you had; the area = 63; and length is w+2.....

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More answers

amistre64
  • amistre64
I missed it when I did (w+2)(w)... it equals w^2 + 2w.... NOT: w^2 + w my mistake
anonymous
  • anonymous
you mean to tell me we did alllllllllll that for nothing...........it did seem a little complicated.....lol
amistre64
  • amistre64
lol.....good practice I guess :)
anonymous
  • anonymous
so our final answer is...........
amistre64
  • amistre64
Lenght = 9 and width =7 is what we were supposed to get, and that i the correct answer.
amistre64
  • amistre64
so this question here is a triangle: and we use the formula h^2 + b^2 = d^2 or whatever letter you wanna use. we know that the span is 4ft longer than its height
amistre64
  • amistre64
lets set it up: h^2 + (h+4)^2 = 20^2 h^2 + h^2 +8h +16 = 400
amistre64
  • amistre64
2h^2 +8h +16 -400 =0 2h^2 +8h -384 = 0 2(h^2 +4h -192) = 0...I hope im right so far :)
amistre64
  • amistre64
2(0) = 0 so... h^2 +4h -192 = 0 h= -4/2 + sqrt(16 - (4)(1)(192))/2
amistre64
  • amistre64
h= -2 + sqrt(784)/2
amistre64
  • amistre64
h = 14 - 2 = 12 h=12 and span =16.
amistre64
  • amistre64
when I double check, it works like a dream :)
anonymous
  • anonymous
looks about right to me
amistre64
  • amistre64
i had to get my brains back :)
anonymous
  • anonymous
you been doing too much math.........lol
amistre64
  • amistre64
lol.... i do agree
anonymous
  • anonymous
I wanna be like you when I grow up..........lol!

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