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anonymous
 5 years ago
Find the slope of the line tangent to the curve at x.
y = 7x2 + 5x; x = 11
anonymous
 5 years ago
Find the slope of the line tangent to the curve at x. y = 7x2 + 5x; x = 11

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0When you see slope think derivative? The derivation is the slope at every point of the curve. y'=? Then evaluate y' at x=11

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y = 7x ^{2} + 5x\] \[x = 11\] Take the derivative, so \[y' =14x + 5 \] Then plug in 11, and the slope at x = 11 is 14(11) + 5 = 149

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you!! i saw an example like that on the internet but i didnt think it would be that easy, thank you so much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just posted another question, if u could at least explain to me how it works...
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