Find the slope of the line tangent to the curve at x. y = -7x2 + 5x; x = 11

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Find the slope of the line tangent to the curve at x. y = -7x2 + 5x; x = 11

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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When you see slope think derivative? The derivation is the slope at every point of the curve. y'=? Then evaluate y' at x=11
derivative*
\[y = -7x ^{2} + 5x\] \[x = 11\] Take the derivative, so \[y' =-14x + 5 \] Then plug in 11, and the slope at x = 11 is -14(11) + 5 = -149

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thank you!! i saw an example like that on the internet but i didnt think it would be that easy, thank you so much
Very welcome!
i just posted another question, if u could at least explain to me how it works...

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