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2.99

Oops that's not right sorry

hahhah yeah...

its like solving square roots and radical equations

27

^^ That's the answer sorry about that haha

okay but like how do u do it....hahah

explllain :)

2x^(4/3) = 162
x^(4/3) = 81
x = 81^(3/4)
x = 27

This is because
(x^(4/3))^(3/4) = (81)^(3/4)

\[2x ^{4/3} - 2 = 160\]
\[x ^{4/3} = 81\]
\[\sqrt[3]{x^{4}} = 81\]
\[x ^{4} = 81^{3}\]
x = 27

Make me a lifesaver :)

I beat krb686

thankss guys!!!

thankss guys!!!

i have more questions hold on....hahah

i have more questions hold on....hahah

okay so the next section is inverse relations and functions...

Do you know how to find the domain of a function?

yeaahh

So the domain of the function here is [-2,infinity)

But we have y=-(x+2)^(1/2), so the function is getting smaller for big x

ohh so thats all?

thats easyy

what about if its like... \[y=\sqrt{x+2}+1\]?

No the domain includes values greater than -2

Okay so the inside 2 shifts it to the left 2, and the outside 1 shifts it UP 1

Shift left 2, and increased y intercept by 1

im pretty sure we are only talking about real numbers here

True

hes in college algebra

You should never be an electrical engineer.

or some type of algebra

wait okay so..

see you confused him

what about if theres a number (either neg or pos) before the square root?

umm im not a him if youre talking about me...hahahha

Yeah, stop assuming like how you're assuming it's a real number. She's a girl.

hahha love ya math genius <3 <3

r u guys like math nerds....

I guess you could say that. Soon-to-be engineers.

i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

dont miss me too muchhhhhh!!! hahahhaha

I'll try not to ;)

i like math genius the best...youre the only one who responds to my pointless comments

i like math genius the best...youre the only one who responds to my pointless comments

k bye...for reall..