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anonymous

  • 5 years ago

how do you solve 2x^4/3-2=160?

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  1. anonymous
    • 5 years ago
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    2.99

  2. anonymous
    • 5 years ago
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    Oops that's not right sorry

  3. anonymous
    • 5 years ago
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    hahhah yeah...

  4. anonymous
    • 5 years ago
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    its like solving square roots and radical equations

  5. anonymous
    • 5 years ago
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    27

  6. anonymous
    • 5 years ago
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    ^^ That's the answer sorry about that haha

  7. anonymous
    • 5 years ago
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    okay but like how do u do it....hahah

  8. anonymous
    • 5 years ago
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    explllain :)

  9. anonymous
    • 5 years ago
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    2x^(4/3) = 162 x^(4/3) = 81 x = 81^(3/4) x = 27

  10. anonymous
    • 5 years ago
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    This is because (x^(4/3))^(3/4) = (81)^(3/4)

  11. anonymous
    • 5 years ago
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    \[2x ^{4/3} - 2 = 160\] \[x ^{4/3} = 81\] \[\sqrt[3]{x^{4}} = 81\] \[x ^{4} = 81^{3}\] x = 27

  12. anonymous
    • 5 years ago
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    Make me a lifesaver :)

  13. anonymous
    • 5 years ago
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    I beat krb686

  14. anonymous
    • 5 years ago
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    thankss guys!!!

  15. anonymous
    • 5 years ago
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    thankss guys!!!

  16. anonymous
    • 5 years ago
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    i have more questions hold on....hahah

  17. anonymous
    • 5 years ago
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    i have more questions hold on....hahah

  18. anonymous
    • 5 years ago
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    okay so the next section is inverse relations and functions...

  19. anonymous
    • 5 years ago
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    wait forgett that haha..okay so how do u graph square roots and radical functions like wtff i dont get itt.... one problem is like y=-\[y=-\sqrt{x+2}\]

  20. myininaya
    • 5 years ago
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    Do you know how to find the domain of a function?

  21. anonymous
    • 5 years ago
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    yeaahh

  22. myininaya
    • 5 years ago
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    So the domain of the function here is [-2,infinity)

  23. myininaya
    • 5 years ago
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    If we were looking at y=(x+2)^(1/2) the function would be increasing since the bigger the x the bigger the y.

  24. myininaya
    • 5 years ago
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    But we have y=-(x+2)^(1/2), so the function is getting smaller for big x

  25. anonymous
    • 5 years ago
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    If you can graph the function y = root(x), then take that graph and shift it to the left by 2, and flip it upside down

  26. anonymous
    • 5 years ago
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    ohh so thats all?

  27. anonymous
    • 5 years ago
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    thats easyy

  28. anonymous
    • 5 years ago
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    Yep! When there is an additive factor inside of the function with the x, a positive # shifts to the left and negative shifts to the right. And a negative multipler on the outside flips it upside down.

  29. anonymous
    • 5 years ago
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    No technically the domain includes values less than negative 2, which would be considered i values (or in this case imaginary), this is very useful in electrical engineering where there is an imaginary and real domain. Very useful in euler's method as well. The values don't exist if they are indeterminant or non-existent in general, and krb is correct in the fact that it will be shifted and the values will flip.

  30. anonymous
    • 5 years ago
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    what about if its like... \[y=\sqrt{x+2}+1\]?

  31. myininaya
    • 5 years ago
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    No the domain includes values greater than -2

  32. anonymous
    • 5 years ago
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    Okay so the inside 2 shifts it to the left 2, and the outside 1 shifts it UP 1

  33. anonymous
    • 5 years ago
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    Shift left 2, and increased y intercept by 1

  34. anonymous
    • 5 years ago
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    mathgenius101 is technically correct, if the domain is allowed to include all numbers not just reals.

  35. anonymous
    • 5 years ago
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    He didn't specify if the domain included complex values. So technically there could be a domain x<-2, imaginary is still technically a complex number.

  36. myininaya
    • 5 years ago
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    im pretty sure we are only talking about real numbers here

  37. anonymous
    • 5 years ago
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    True

  38. myininaya
    • 5 years ago
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    hes in college algebra

  39. anonymous
    • 5 years ago
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    You should never be an electrical engineer.

  40. myininaya
    • 5 years ago
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    or some type of algebra

  41. anonymous
    • 5 years ago
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    wait okay so..

  42. myininaya
    • 5 years ago
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    see you confused him

  43. anonymous
    • 5 years ago
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    what about if theres a number (either neg or pos) before the square root?

  44. anonymous
    • 5 years ago
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    umm im not a him if youre talking about me...hahahha

  45. anonymous
    • 5 years ago
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    Multiplied or added/subtracted? Multiplied flips it either up or down, added or subtracted shifts it up or down.

  46. anonymous
    • 5 years ago
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    Yeah, stop assuming like how you're assuming it's a real number. She's a girl.

  47. anonymous
    • 5 years ago
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    hahha love ya math genius <3 <3

  48. anonymous
    • 5 years ago
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    r u guys like math nerds....

  49. anonymous
    • 5 years ago
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    I guess you could say that. Soon-to-be engineers.

  50. anonymous
    • 5 years ago
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    i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

  51. anonymous
    • 5 years ago
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    i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

  52. anonymous
    • 5 years ago
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    dont miss me too muchhhhhh!!! hahahhaha

  53. anonymous
    • 5 years ago
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    I'll try not to ;)

  54. anonymous
    • 5 years ago
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    i like math genius the best...youre the only one who responds to my pointless comments

  55. anonymous
    • 5 years ago
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    i like math genius the best...youre the only one who responds to my pointless comments

  56. anonymous
    • 5 years ago
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    k bye...for reall..

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