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anonymous
 5 years ago
how do you solve 2x^4/32=160?
anonymous
 5 years ago
how do you solve 2x^4/32=160?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oops that's not right sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its like solving square roots and radical equations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^^ That's the answer sorry about that haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay but like how do u do it....hahah

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02x^(4/3) = 162 x^(4/3) = 81 x = 81^(3/4) x = 27

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is because (x^(4/3))^(3/4) = (81)^(3/4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2x ^{4/3}  2 = 160\] \[x ^{4/3} = 81\] \[\sqrt[3]{x^{4}} = 81\] \[x ^{4} = 81^{3}\] x = 27

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Make me a lifesaver :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have more questions hold on....hahah

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have more questions hold on....hahah

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so the next section is inverse relations and functions...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait forgett that haha..okay so how do u graph square roots and radical functions like wtff i dont get itt.... one problem is like y=\[y=\sqrt{x+2}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to find the domain of a function?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0So the domain of the function here is [2,infinity)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0If we were looking at y=(x+2)^(1/2) the function would be increasing since the bigger the x the bigger the y.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0But we have y=(x+2)^(1/2), so the function is getting smaller for big x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you can graph the function y = root(x), then take that graph and shift it to the left by 2, and flip it upside down

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yep! When there is an additive factor inside of the function with the x, a positive # shifts to the left and negative shifts to the right. And a negative multipler on the outside flips it upside down.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No technically the domain includes values less than negative 2, which would be considered i values (or in this case imaginary), this is very useful in electrical engineering where there is an imaginary and real domain. Very useful in euler's method as well. The values don't exist if they are indeterminant or nonexistent in general, and krb is correct in the fact that it will be shifted and the values will flip.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about if its like... \[y=\sqrt{x+2}+1\]?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0No the domain includes values greater than 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay so the inside 2 shifts it to the left 2, and the outside 1 shifts it UP 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Shift left 2, and increased y intercept by 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mathgenius101 is technically correct, if the domain is allowed to include all numbers not just reals.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0He didn't specify if the domain included complex values. So technically there could be a domain x<2, imaginary is still technically a complex number.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0im pretty sure we are only talking about real numbers here

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0hes in college algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You should never be an electrical engineer.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0or some type of algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about if theres a number (either neg or pos) before the square root?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0umm im not a him if youre talking about me...hahahha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiplied or added/subtracted? Multiplied flips it either up or down, added or subtracted shifts it up or down.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, stop assuming like how you're assuming it's a real number. She's a girl.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hahha love ya math genius <3 <3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0r u guys like math nerds....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess you could say that. Soontobe engineers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont miss me too muchhhhhh!!! hahahhaha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i like math genius the best...youre the only one who responds to my pointless comments

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i like math genius the best...youre the only one who responds to my pointless comments
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