anonymous
  • anonymous
how do you solve 2x^4/3-2=160?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
2.99
anonymous
  • anonymous
Oops that's not right sorry
anonymous
  • anonymous
hahhah yeah...

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anonymous
  • anonymous
its like solving square roots and radical equations
anonymous
  • anonymous
27
anonymous
  • anonymous
^^ That's the answer sorry about that haha
anonymous
  • anonymous
okay but like how do u do it....hahah
anonymous
  • anonymous
explllain :)
anonymous
  • anonymous
2x^(4/3) = 162 x^(4/3) = 81 x = 81^(3/4) x = 27
anonymous
  • anonymous
This is because (x^(4/3))^(3/4) = (81)^(3/4)
anonymous
  • anonymous
\[2x ^{4/3} - 2 = 160\] \[x ^{4/3} = 81\] \[\sqrt[3]{x^{4}} = 81\] \[x ^{4} = 81^{3}\] x = 27
anonymous
  • anonymous
Make me a lifesaver :)
anonymous
  • anonymous
I beat krb686
anonymous
  • anonymous
thankss guys!!!
anonymous
  • anonymous
thankss guys!!!
anonymous
  • anonymous
i have more questions hold on....hahah
anonymous
  • anonymous
i have more questions hold on....hahah
anonymous
  • anonymous
okay so the next section is inverse relations and functions...
anonymous
  • anonymous
wait forgett that haha..okay so how do u graph square roots and radical functions like wtff i dont get itt.... one problem is like y=-\[y=-\sqrt{x+2}\]
myininaya
  • myininaya
Do you know how to find the domain of a function?
anonymous
  • anonymous
yeaahh
myininaya
  • myininaya
So the domain of the function here is [-2,infinity)
myininaya
  • myininaya
If we were looking at y=(x+2)^(1/2) the function would be increasing since the bigger the x the bigger the y.
myininaya
  • myininaya
But we have y=-(x+2)^(1/2), so the function is getting smaller for big x
anonymous
  • anonymous
If you can graph the function y = root(x), then take that graph and shift it to the left by 2, and flip it upside down
anonymous
  • anonymous
ohh so thats all?
anonymous
  • anonymous
thats easyy
anonymous
  • anonymous
Yep! When there is an additive factor inside of the function with the x, a positive # shifts to the left and negative shifts to the right. And a negative multipler on the outside flips it upside down.
anonymous
  • anonymous
No technically the domain includes values less than negative 2, which would be considered i values (or in this case imaginary), this is very useful in electrical engineering where there is an imaginary and real domain. Very useful in euler's method as well. The values don't exist if they are indeterminant or non-existent in general, and krb is correct in the fact that it will be shifted and the values will flip.
anonymous
  • anonymous
what about if its like... \[y=\sqrt{x+2}+1\]?
myininaya
  • myininaya
No the domain includes values greater than -2
anonymous
  • anonymous
Okay so the inside 2 shifts it to the left 2, and the outside 1 shifts it UP 1
anonymous
  • anonymous
Shift left 2, and increased y intercept by 1
anonymous
  • anonymous
mathgenius101 is technically correct, if the domain is allowed to include all numbers not just reals.
anonymous
  • anonymous
He didn't specify if the domain included complex values. So technically there could be a domain x<-2, imaginary is still technically a complex number.
myininaya
  • myininaya
im pretty sure we are only talking about real numbers here
anonymous
  • anonymous
True
myininaya
  • myininaya
hes in college algebra
anonymous
  • anonymous
You should never be an electrical engineer.
myininaya
  • myininaya
or some type of algebra
anonymous
  • anonymous
wait okay so..
myininaya
  • myininaya
see you confused him
anonymous
  • anonymous
what about if theres a number (either neg or pos) before the square root?
anonymous
  • anonymous
umm im not a him if youre talking about me...hahahha
anonymous
  • anonymous
Multiplied or added/subtracted? Multiplied flips it either up or down, added or subtracted shifts it up or down.
anonymous
  • anonymous
Yeah, stop assuming like how you're assuming it's a real number. She's a girl.
anonymous
  • anonymous
hahha love ya math genius <3 <3
anonymous
  • anonymous
r u guys like math nerds....
anonymous
  • anonymous
I guess you could say that. Soon-to-be engineers.
anonymous
  • anonymous
i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3
anonymous
  • anonymous
i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3
anonymous
  • anonymous
dont miss me too muchhhhhh!!! hahahhaha
anonymous
  • anonymous
I'll try not to ;)
anonymous
  • anonymous
i like math genius the best...youre the only one who responds to my pointless comments
anonymous
  • anonymous
i like math genius the best...youre the only one who responds to my pointless comments
anonymous
  • anonymous
k bye...for reall..

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