how do you solve 2x^4/3-2=160?

- anonymous

how do you solve 2x^4/3-2=160?

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- katieb

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- anonymous

2.99

- anonymous

Oops that's not right sorry

- anonymous

hahhah yeah...

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## More answers

- anonymous

its like solving square roots and radical equations

- anonymous

27

- anonymous

^^ That's the answer sorry about that haha

- anonymous

okay but like how do u do it....hahah

- anonymous

explllain :)

- anonymous

2x^(4/3) = 162
x^(4/3) = 81
x = 81^(3/4)
x = 27

- anonymous

This is because
(x^(4/3))^(3/4) = (81)^(3/4)

- anonymous

\[2x ^{4/3} - 2 = 160\]
\[x ^{4/3} = 81\]
\[\sqrt[3]{x^{4}} = 81\]
\[x ^{4} = 81^{3}\]
x = 27

- anonymous

Make me a lifesaver :)

- anonymous

I beat krb686

- anonymous

thankss guys!!!

- anonymous

thankss guys!!!

- anonymous

i have more questions hold on....hahah

- anonymous

i have more questions hold on....hahah

- anonymous

okay so the next section is inverse relations and functions...

- anonymous

wait forgett that haha..okay so how do u graph square roots and radical functions like wtff i dont get itt.... one problem is like y=-\[y=-\sqrt{x+2}\]

- myininaya

Do you know how to find the domain of a function?

- anonymous

yeaahh

- myininaya

So the domain of the function here is [-2,infinity)

- myininaya

If we were looking at y=(x+2)^(1/2) the function would be increasing since the bigger the x the bigger the y.

- myininaya

But we have y=-(x+2)^(1/2), so the function is getting smaller for big x

- anonymous

If you can graph the function y = root(x), then take that graph and shift it to the left by 2, and flip it upside down

- anonymous

ohh so thats all?

- anonymous

thats easyy

- anonymous

Yep! When there is an additive factor inside of the function with the x, a positive # shifts to the left and negative shifts to the right.
And a negative multipler on the outside flips it upside down.

- anonymous

No technically the domain includes values less than negative 2, which would be considered i values (or in this case imaginary), this is very useful in electrical engineering where there is an imaginary and real domain. Very useful in euler's method as well. The values don't exist if they are indeterminant or non-existent in general, and krb is correct in the fact that it will be shifted and the values will flip.

- anonymous

what about if its like... \[y=\sqrt{x+2}+1\]?

- myininaya

No the domain includes values greater than -2

- anonymous

Okay so the inside 2 shifts it to the left 2, and the outside 1 shifts it UP 1

- anonymous

Shift left 2, and increased y intercept by 1

- anonymous

mathgenius101 is technically correct, if the domain is allowed to include all numbers not just reals.

- anonymous

He didn't specify if the domain included complex values. So technically there could be a domain x<-2, imaginary is still technically a complex number.

- myininaya

im pretty sure we are only talking about real numbers here

- anonymous

True

- myininaya

hes in college algebra

- anonymous

You should never be an electrical engineer.

- myininaya

or some type of algebra

- anonymous

wait okay so..

- myininaya

see you confused him

- anonymous

what about if theres a number (either neg or pos) before the square root?

- anonymous

umm im not a him if youre talking about me...hahahha

- anonymous

Multiplied or added/subtracted?
Multiplied flips it either up or down, added or subtracted shifts it up or down.

- anonymous

Yeah, stop assuming like how you're assuming it's a real number. She's a girl.

- anonymous

hahha love ya math genius <3 <3

- anonymous

r u guys like math nerds....

- anonymous

I guess you could say that. Soon-to-be engineers.

- anonymous

i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

- anonymous

i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

- anonymous

dont miss me too muchhhhhh!!! hahahhaha

- anonymous

I'll try not to ;)

- anonymous

i like math genius the best...youre the only one who responds to my pointless comments

- anonymous

i like math genius the best...youre the only one who responds to my pointless comments

- anonymous

k bye...for reall..

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