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anonymous
 5 years ago
find the volume of the solid generated by revolving the line x=4.The region bounded by the two parabolas x=(yy^2),x=(y^23).
anonymous
 5 years ago
find the volume of the solid generated by revolving the line x=4.The region bounded by the two parabolas x=(yy^2),x=(y^23).

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sounds like a torus...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0need to figure out the solution to the system of equations to know what our "bounds" are gonna be...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i got an idea, but its just to early in the morning to get it right in me head.....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the bounds for the integral are gonna be [1,(3/2)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That is an odd region...is it the odd oval shape?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(S) yy^2 dy = (1/2)y^2 (1/3) y^3 13/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its a funky shape fer sure :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use circular ring method..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That shape isn't circular...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know the answer but i dont know the solution..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your one step ahead of me then :) I am just trying to find the area of the shape

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0for F(x) + get an area of 7/24....which could be totally wrong, but ill see :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't understand exactly which region he is asking for...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0G(x) = (S) y^23 dy = (1/3)y^3 3y  1,(3/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0These are the graphs http://www.wolframalpha.com/input/?i=x+%3D+yy^2%2C+x%3D+y^23%2C+x%3D4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Why does this site suck at showing links...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the region for the area is between y=1 and y=(3/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So it's the odd oval shape in the center http://www.wolframalpha.com/input/?i=x+%3D+yy^2%2C+x%3D+y^23

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i solved the system of equations and got y=1 and y=(3/2) as solutions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes i see those bounds

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0If I did it right; the area of F(x) = 7/24. Now I need to subtract area of G(x) right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So where exactly does the line x = 4 come in then

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you spin the area around x=4 to find the area of the torus shape

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i hope its the center :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0G(3/2) = 27/8 if Im doing it right :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where should i put the strip??is it horizontal or vertical?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0area of G(x) = 145/24 ? Horizontal I beleive

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0total area of shape is F(x)  G(x) = 152/24

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how do we spin it? multiply by circumference of the circle?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0integrate from 0 to 2*pi

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I can find the area between curves alright, but after that I get lost :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Area = 38/6 = 19/3...thats as far as I can reduce it; if its right

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how do we integrate the spin? Do we need to find the domain of the area are anything?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.....comeon..your smarter than me for sure :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i thought it was the integral from 0 to 2*pi, but that wouldn't make much sense in this case

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What about using the ring method

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That would probably just be much more difficult

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0not that versed in the ring method...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sounds like we'd integrate with respect to the radius....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes the inner radius would be the maximum for the first equation, and the outer radius would be the maximum for the 2nd i believe

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0gotta go back and find the bends then :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0one of those bounds is x=1/4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is that right? yy^2 x'=12y=0 y=1/2. .5.5^2 = .25 x=1/4 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My brain hurts lol. Okay so you're deriving yy^2, solving for y, and plugging it back in?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y^2 3 x'=2y=0 y=0 other bound is x=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah that seems right

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep, only thing I can do :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sp we got our bends at x=3 and x=1/4....now what?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0spin it at x=4 somehow

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0each slice is spin from 3 to 1/4 in dx increments and then add them all up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im confused on the area

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0make it easier and spin add 4 to x so that we have the middle at 0 and our limits at 1 and the other at 4.25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah that's what i did actually :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0which area :) the area between the curves?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, the integral of x = yy^2 would give the area under the parabola, but how would you remove the sections on the sides to get the torus

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or i should say...to the right of the parabola

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the two equations meet at the points 1 and 3/2; so these are the bounds we use. to find the area right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0back in algebra here :) when yy^2 = y^23 we get solutions to the equations :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02y^2 y 3 =0 (y...)(y+....)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I use that to find the area of F(x) and G(x) then: F(x)G(x) gives us the area we need

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now, since we are talking about spinning a circle; do we (S) 2pi(x)(area)? dx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it should be the same concept as finding the area between curves; use the lower and upper bounds of x and subtract them?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cant hurt to try: (S) 2pi(x)(19/3) dx = 19pi(x^2)/3  1,4.25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0114.39583333(pi)  6.3333333333(pi)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I get 108.0625 pi....but am I right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ill need alot more practice for this I guess :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0v=85.902 cubic units is what the person said to begin with; and that doesnt match mine

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah it doesn't, my brain is too fried for this right now, I've got diff eq in 5 hours, best of luck though

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the key lies in the y axis. distance from the y axis bounds i think..not the xaxis

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is the integral of 1/((x+2)√(x+3))

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im wrong somewhere :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i need more practice on integrals... .

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0have you intergrated by parts?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah...but dunno if its correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0did you do it more than once?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(S) 1/x+2 dx = ln(x+2) that much works out

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i gotta get some sleep :)....chat with ya later think...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay amistre...btw u have taken u=1/x+2?
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