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anonymous
 5 years ago
I need to find the slope and yintercept of 5x2y=3. I think the slope is 5/2 and the yintercept is 3/2???? Is this correct?
anonymous
 5 years ago
I need to find the slope and yintercept of 5x2y=3. I think the slope is 5/2 and the yintercept is 3/2???? Is this correct?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it is .....can we work on a partial diffferential problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry don't have any problems like that right now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i do have ...and need someone to workout on it...i want to match my answer with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0slope and intercept on y axis are correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats the second order partial derivative when function f(x,y) =Sin xy. both wrt x and y

singularity
 5 years ago
Best ResponseYou've already chosen the best response.0Thinker: The derivative of sin(f(x,y)) w.r.t. x would be cos(f(x,y)) * df(x,y)/dx. In other words, take the derivative of cosine, then take the derivative of what's inside the cosine. Applying that formula, the d(sin(xy))/dx = cos(xy)y. Does that help?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have differentiated w.r.t. x and got −y2Sinxy but to find 2nd order part. derv. i have differentiated this w.r.t. y and i have got −xySinxy−cosxy is this correct?

singularity
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not quite sure what '2nd order partial derivative' is (and I'm confused by your notation). But if you take the second derivative of sin(xy) w.r.t. x, you get y^2*sin(xy) (negative y squared times the sine of x times y). The second deriv wrt y is x^2*sin(xy). You can also take partial derivatives wrt x, then the partial derivative of that wrt to y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i have got 1st derv(after diff wrt x, say eq 1) as wat you got, now i need to differentiate this eq. wrt y...i.e. eq 1 wrt 'y'

singularity
 5 years ago
Best ResponseYou've already chosen the best response.0Then you'll need to use the product rule on cos(xy)y. For the product rule, u=cos(xy), and v=y. The product rule is (uv)'=u'v+uv' (the derivative of u times v equals the derivative of u times y plus u times the derivative of v. I think you have enough to complete the problem now.
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