If sally can paint a house in 4 hours, and john can paint the same house in 6 hours. How long will it take if they paint the house together?
Stacey Warren - Expert brainly.com
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1 hour and 20 minutes I think
I don't remember a formula for this, but imagine a house requiring 100 units of paint.
Sally does it in 4 hours, that's 25 units per hour.
John does it in 2 hours, or 50 units per.
Together, it's 75 units per hour.
(100/75) = (4/3) = 1 hr 20 mins
Since there is only two, use the product over sum. (6 x 4)/(6+4)
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Or 24/10=2.4 hours
How much does each pain tin 1 hour.
S = 1/4 of a house
J = 1/6 of a house
S+J = how much they paint together in 1 hour:
1/4 + 1/6 = (6+4)/24 = 10/24 = 5/12
Together they paint 5/12 part of the house in one hour.
x amount of hours times (5/12) will equal 12/12, or the whole thing.
(5/12)x = 12/12 = 1
x = 1(12/5) = 12/5
x= 2 and 2 fifths of an hour.
what is 2/5 of an hour? Its (60minutes/5) times 2
12(2) = 24 minutes
2 hours and 24 minutes to paint the house.
Oh, I used 4 hrs and 2 hrs, oops.
Krb is right if they are unionized :)
A hint, when the two work together, the job should be completed in less time of the quickest one.
before I knew how to work these, I looked at it from my carpentry years and thought.... when i had help it usually slowed me down :)