anonymous
  • anonymous
click it
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
yay
anonymous
  • anonymous
so which grade are you in jones?
anonymous
  • anonymous
i dunno why this happens always...it gets posted more than once!!! lol

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More answers

anonymous
  • anonymous
\[y>x+4\]\[y \ge 1/2x +3\]\[y<3x-1\]\[1. x+y<-6\]\[2. y
anonymous
  • anonymous
9th
anonymous
  • anonymous
and match the answer with the problme you answered.. the editor messed it up
anonymous
  • anonymous
u say that u got 5 equations and u need points so that u may plot the graphs, did i get u right?
anonymous
  • anonymous
yesir
anonymous
  • anonymous
okay i'll do one for you , and you may follow up with the rest so that u may learn how to do it..is that fine jones?
anonymous
  • anonymous
yes it is
anonymous
  • anonymous
but i will post my answers for you to check tho.. is THAT ok.....lol.
anonymous
  • anonymous
yeah...will try..lol...
anonymous
  • anonymous
\[y > x + 4\] http://tinyurl.com/45oujoz
anonymous
  • anonymous
\[y \ge (1/2)x + 3\] http://tinyurl.com/4q2yx6l
anonymous
  • anonymous
lol krb thx lol
anonymous
  • anonymous
\[y < 3x-1\] http://tinyurl.com/6zhwlty
anonymous
  • anonymous
umm thinker you can still post. so i can see if i knoew how to do them
anonymous
  • anonymous
x + y < -6 http://tinyurl.com/6dtjurx
anonymous
  • anonymous
y < x http://tinyurl.com/4aezqtn
anonymous
  • anonymous
jones, if u just want the answers , u can try http://www.wolframalpha.com/input/?i=solve+y%3E%3D%281%2F2%29x%2B3 for now for y>=1/2x+3....but the actual procedure to solve these is to substitute the x to get y and u can try subs a few lie this, and when u finally join these points, u get a line, depending whether the inequality is > or < u can shade the graph.. is that making sense?
anonymous
  • anonymous
1) y > x + 4 Remove the > and pretend it's an = sign. Graph y = x + 4 Shade the upper region.
anonymous
  • anonymous
2) \[y \ge (1/2)x + 3\] Same steps as above Graph y = (1/2)x + 3 Shade the upper region, the line should be solid. Above it should be a dashed line
anonymous
  • anonymous
3) y < 3x - 1 Graph y = 3x-1 Dashed line, shade lower region. You get the idea?
anonymous
  • anonymous
when inequality is '>' shade the greater ( upper) region , when its '<' shade the lesser(lower) area
anonymous
  • anonymous
got it jones?

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