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anonymous

  • 5 years ago

Help me to understand this please.

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  1. anonymous
    • 5 years ago
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    \[e^{x}\times \sin x \times -\cos x\]

  2. anonymous
    • 5 years ago
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    Here is the graph of that function. http://tinyurl.com/4cazsvl As x approaches -infinity, sin and cos simply oscillate,while e^x approaches 0, which makes the limit 0. As x approaches infinity, e^x becomes extremely large, making the function oscillate wildly.

  3. anonymous
    • 5 years ago
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    uh thanks one more thing what is the solutıon of the equation \[-\cos x \times \sin x = ?\]

  4. anonymous
    • 5 years ago
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    So you need to find solutions that cause sin(x) = 0 and cos(x) = 0 Sin(x) = 0 when x = pi * n Cos(x) = 0 when x = (pi/2) * n Combine the two, so every multiple of pi/2 = 0

  5. anonymous
    • 5 years ago
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    thank you so much for your reply but what i ask is exactly this =>, for ex: \[e^{x}\times(-\sin x)\times(-\sin x) = e^{x}\times(\sin^{2}x)\] and what is: \[e^{x}\times(\sin x)\times(-\cos x) = ?\]

  6. anonymous
    • 5 years ago
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    Well your first equation is an identity. The solutions to the second equation are exactly the same as what I posted above. I'm still not 100% are you asking for the roots?

  7. anonymous
    • 5 years ago
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    yes i am asking for the roots for \[- \cos x \times \sin x =\] or \[-\sin x \times \cos x =\]

  8. anonymous
    • 5 years ago
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    Okay then \[(\pi/2)*n\] n is any integer

  9. anonymous
    • 5 years ago
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    thank you very much

  10. anonymous
    • 5 years ago
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    You're welcome

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