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anonymous
 5 years ago
Help me to understand this please.
anonymous
 5 years ago
Help me to understand this please.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[e^{x}\times \sin x \times \cos x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is the graph of that function. http://tinyurl.com/4cazsvl As x approaches infinity, sin and cos simply oscillate,while e^x approaches 0, which makes the limit 0. As x approaches infinity, e^x becomes extremely large, making the function oscillate wildly.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0uh thanks one more thing what is the solutıon of the equation \[\cos x \times \sin x = ?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you need to find solutions that cause sin(x) = 0 and cos(x) = 0 Sin(x) = 0 when x = pi * n Cos(x) = 0 when x = (pi/2) * n Combine the two, so every multiple of pi/2 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you so much for your reply but what i ask is exactly this =>, for ex: \[e^{x}\times(\sin x)\times(\sin x) = e^{x}\times(\sin^{2}x)\] and what is: \[e^{x}\times(\sin x)\times(\cos x) = ?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well your first equation is an identity. The solutions to the second equation are exactly the same as what I posted above. I'm still not 100% are you asking for the roots?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i am asking for the roots for \[ \cos x \times \sin x =\] or \[\sin x \times \cos x =\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay then \[(\pi/2)*n\] n is any integer
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