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anonymous
 5 years ago
If w=x^2+yz+sin t & x+y=t , then how to find part.dervivative of w wrt y ? plz click to find more.....
anonymous
 5 years ago
If w=x^2+yz+sin t & x+y=t , then how to find part.dervivative of w wrt y ? plz click to find more.....

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[w = x ^{2} + y  z + \sin(t)\] \[x + y = t\] Sorry which derivative are you looking for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we have to find \[(dough w/dough y)_{x,z}\].partial derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm honestly not sure what you mean by that notation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there's no notation here, consider dough = d (dw/dx)\[_{x,z}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(\[(dw/dx)_{x,z}\] what does this x,z mean here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry , it is \[(dw/dy)_{x,z}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use \partial to get \[\partial\] if you like

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks eb... can u temme wat foes 'x,z' mean here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(\partial w/ \partial y)_{x,z}\] this is the actual notation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay I think that means find the derivative of w with respect to y, and evaluate at x,z? Not exactly sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i wanted to know what this x,z means...i guess those are independent variables? is it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0w=x2+y−z+sin(t) x+y=t w=x2+y−z+sin(x+y) assuming w=f(x,y,z) (dw/dy) =0+1+0+cos(x+y) =1+Cos(x+y)
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