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anonymous
 5 years ago
If the rotation matrix in the rotation equation is matrix[x_y]=matrix[√(2)/2,√(2)/2,_√(2)/2,√(2)/2,]*matrix[x'_y']. What angle of rotation is being used?
anonymous
 5 years ago
If the rotation matrix in the rotation equation is matrix[x_y]=matrix[√(2)/2,√(2)/2,_√(2)/2,√(2)/2,]*matrix[x'_y']. What angle of rotation is being used?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just wrote a huge piece and this site kiboshed what I wrote. Did you get anything for this question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Basically, identify the entries in your matrix with each of the trig. functions that describe a rotation matrix in two dimensions. You should have then,\[\sin \theta = \frac{1}{\sqrt{2}}\]and \[\cos \theta =\frac{1}{\sqrt{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In one rotation, \[\sin \theta = \frac{1}{\sqrt{2}} \rightarrow \theta =225^o, 315^o\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\cos \theta = \frac{1}{\sqrt{2}} \rightarrow \theta = 135^o, 225^o\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The only angle BOTH trig. functions have in common is 225 degrees. Unless I've misread your matrix entries, this is the angle of rotation.
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