anonymous
  • anonymous
If something is an integer, can I take the partial derivative of it with respect to it or not?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Do you have the function available?
anonymous
  • anonymous
Yes I do. y=m(n^2)r
anonymous
  • anonymous
\[y=mn^2r\]?

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anonymous
  • anonymous
Correct.
anonymous
  • anonymous
Let me check something.
anonymous
  • anonymous
ok
anonymous
  • anonymous
I'm pretty sure the answer is no, but I wanted to check through some of my advanced stuff. Basically, there's a theorem that says if a function is differentiable, it's continuous. This function is not continuous (this is what I wanted to check - I wanted to see if there was a definition of continuity outside the real numbers), so the function cannot be differentiable. This is the problem had by another integral function, n!. It was extended into the Gamma Function, which spat out n! but had values in between (making continuous). Mathematicians wanted this so they could take the derivative of n!.
anonymous
  • anonymous
Thanks!
myininaya
  • myininaya
I agree with lokisan. You can take the partial derivative of an integer with respect to any variable but not a constant. Do I make sense?
anonymous
  • anonymous
So I'm unable to take the partial derivative of n in the following equation: \[Fc = (4\pi ^{2}mn^{2}r)/T^{2}\] where n is an integer number having no uncertainty

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