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anonymous
 5 years ago
Canoeing. during the first part of a canoe trip Ken covered 60km at a certain speed.He then traveled 24 km at a speed that was 4km/h slower.If the total time for the trip was 8 hrs.,what was the speed on each part of the trip?
anonymous
 5 years ago
Canoeing. during the first part of a canoe trip Ken covered 60km at a certain speed.He then traveled 24 km at a speed that was 4km/h slower.If the total time for the trip was 8 hrs.,what was the speed on each part of the trip?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Set up your equations. Let v be the speed of the first trip, t_1 the time taken in the first trip and t_2 the second time. Using the definition,\[speed=\frac{distance}{time}\]then\[distance=(speed)(time)\]For the first leg\[60=vt_1\]and the second\[24=(v4)t_2\]We know also that \[t_1+t_2=8\]You have three equations in three unknowns which you can now solve.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[t_2=8t_1\]which you sub. into the equation 24=(v4)... to get\[24=(v4)(8t)\]where I've dropped the subscript on t_1. So\[t=\frac{568v}{4v}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Substitute this into the first equation,\[60=v(\frac{568v}{4v}) \rightarrow 24060v=56v8v^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is quadratic in v\[8v^2116v+240=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which can be factored as\[4(v12)(2v5)=0\rightarrow v=12,\frac{5}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If v=5/2, t=24 hours, which is outside your 8 hour limit. The other solution, v=12km/h yields t=5 hrs. So the first part of the trip took 5 hours, the second part therefore took the remaining 3 hrs.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Damn, I answered the wrong question.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Hey it looks good to me, I liked the step by step explanation. I am sure Anointed will appreciate it.

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Agree, I learned something.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Looks good to me.These kind of equations are a little complicated but you made it look so easy! Thanks!
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