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anonymous

  • 5 years ago

I know it is not a maths question, but I couldn't find a physics study group, so: An electric radiator which is an ordinary constant resistor emits a heating power of 750 W at a mains supply voltage of 230 V. What is the total heating power in each respective instance when two such radiators are connected a) in parallel, and b) in series to the 230 V supply voltage? i think i need to find the resistance of radiator first am I right?

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  1. anonymous
    • 5 years ago
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    i found the resistance of each radiator to be 70.5333 ohms, but what do I do now?

  2. anonymous
    • 5 years ago
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    You're right about the first part.

  3. anonymous
    • 5 years ago
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    You next have to set up your circuit where each radiator is represented as a resistor.

  4. anonymous
    • 5 years ago
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    i did, i have drawings ow both cases, series and parallel

  5. anonymous
    • 5 years ago
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    Whenever I see resistance, voltage and power, I think of the following:\[V=IR\]and\[P=IV\]Eliminate current as such\[I=V/R \rightarrow P =(V/R)V=\frac{V^2}{R}\]

  6. anonymous
    • 5 years ago
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    The resistance here will be the effective resistance of the circuit. For the parallel case, \[\frac{1}{R}+\frac{1}{R}=\frac{1}{R_{eff}} \rightarrow R_{eff}=\frac{R}{2}\]and so to find the power for parallel:\[P=\frac{V^2}{R_{eff}}=\frac{V^2}{R/2}=\frac{2V^2}{R}\approx \frac{2 \times 230^2}{70.53}=1500W\]

  7. anonymous
    • 5 years ago
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    For the series case, \[R+R=R_{eff} \rightarrow P=\frac{V^2}{R_{eff}}\approx \frac{230^2}{2 \times 70.53} \approx 375W\]

  8. anonymous
    • 5 years ago
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    great, I understand it now! THANX, you are a leal lifesaver, i wish i could become your fan again

  9. anonymous
    • 5 years ago
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    wait, let me create another account and fan you once more...

  10. anonymous
    • 5 years ago
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    [thumbs up] :)

  11. anonymous
    • 5 years ago
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    here I am

  12. anonymous
    • 5 years ago
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    lol awesome

  13. anonymous
    • 5 years ago
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    :( do not see the fan button :( something is wrong... w8 let me try some proxy manipulation...

  14. anonymous
    • 5 years ago
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    I've heard people say they have to refresh the page or something...in any case, at least you have a cool login.

  15. anonymous
    • 5 years ago
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    Ah...excellent!

  16. anonymous
    • 5 years ago
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    yay, my little hack worked, appearently openstudy wont allow liking on a same user from one IP address, so i used some proxy server to do it

  17. anonymous
    • 5 years ago
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    smart!

  18. anonymous
    • 5 years ago
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    let me try again..

  19. anonymous
    • 5 years ago
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    You know, I think there is something for physics on this openstudy site. I haven't checked properly, but I saw something about physics on the homepage. You have to load more or something...

  20. anonymous
    • 5 years ago
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    click on more groups, and there's something callled physics classical openstudy something.

  21. anonymous
    • 5 years ago
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    yes...that's it

  22. anonymous
    • 5 years ago
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    ^^

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spraguer (Moderator)
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