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anonymous

  • 5 years ago

if h,s, V be the height, Curved surface area and volume of a cone respectively then 3piVh^3 - s^2h^2 + 9V^2 is: NOTE PI = 22/7 or 3.14

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  1. anonymous
    • 5 years ago
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    sstarica do u want options

  2. anonymous
    • 5 years ago
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    you mean \[(3\pi Vh)^3 - s^2h^2 + 9V^2\] so what's the problem?

  3. anonymous
    • 5 years ago
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    no sstarica

  4. anonymous
    • 5 years ago
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    it is only h^3

  5. anonymous
    • 5 years ago
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    so you have to solve it

  6. anonymous
    • 5 years ago
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    then why do you have 3 piV multiplied by h?

  7. anonymous
    • 5 years ago
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    i dodn't undeand rst

  8. anonymous
    • 5 years ago
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    you have 3piVh ^3 right?

  9. anonymous
    • 5 years ago
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    yes of course

  10. anonymous
    • 5 years ago
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    you want to solve the equation?

  11. anonymous
    • 5 years ago
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    yes

  12. anonymous
    • 5 years ago
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    but your question is unfortunately unclear, what is excatly that you want?

  13. anonymous
    • 5 years ago
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    SEE i am giving you V= 1/3 * pi * r^2 * h

  14. anonymous
    • 5 years ago
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    lol

  15. anonymous
    • 5 years ago
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    AND S = pi^2r^2(root of (r^2 + h^2))

  16. anonymous
    • 5 years ago
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    so you don't know the answer of only 8th standard

  17. anonymous
    • 5 years ago
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    no now, I got you. :)

  18. anonymous
    • 5 years ago
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    oh k

  19. anonymous
    • 5 years ago
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    ANSWER IT

  20. anonymous
    • 5 years ago
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    excuse me, you're the one who asked for help, why are you being so boiled up? It's rude, please be polite.

  21. anonymous
    • 5 years ago
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    okey

  22. anonymous
    • 5 years ago
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    all you have to do is substitute V and S in the equation and simplify.

  23. anonymous
    • 5 years ago
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    THIS IS THE PROBLEM THAT I M FACING THE ANSWER IS NOT IN OPTIONS

  24. anonymous
    • 5 years ago
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    and when you do that you get in the end.\[\pi^2r^2h^4 - 4\pi r^4h^2(r^2 + h^2) + 1/3 \pi r^2h\]

  25. anonymous
    • 5 years ago
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    yes i did that

  26. anonymous
    • 5 years ago
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    ofcourse you won't get it corret in the first place, try again. What are the options, tell me?

  27. anonymous
    • 5 years ago
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    okey i m giving the options

  28. anonymous
    • 5 years ago
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    1) option - 2

  29. anonymous
    • 5 years ago
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    2) option - 0

  30. anonymous
    • 5 years ago
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    3) option - 2pi

  31. anonymous
    • 5 years ago
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    4) option - 3(pi)^2

  32. anonymous
    • 5 years ago
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    I've made a mistake, in the end of the answer I gave you above it's supposed to be \[3\pi r^2h\] and note 1/3 pir^2h

  33. anonymous
    • 5 years ago
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    not*

  34. anonymous
    • 5 years ago
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    the answer is 0 !

  35. anonymous
    • 5 years ago
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    here the solution is : first you'll substitute the given in the formula and you will end up with this: \[\pi^2 r^2h^4 - 4 \pi^2r^4h^2(r^2 + h^2) + \pi^2r^4h^2\] then simplify, it's a long step but in the end you will end up with : \[-3\pi^2r^2h^4 - 3\pi^2r^2h^2\] = \[-3\pi^2h^2(r^2h^2 - r^2h^2)\] = \[-3\pi^2h^2\] x 0 = 0 That's it :)

  36. anonymous
    • 5 years ago
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    wait that's wrong >_<

  37. anonymous
    • 5 years ago
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    this has caused me a headache._.

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