At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
sstarica do u want options
you mean \[(3\pi Vh)^3 - s^2h^2 + 9V^2\] so what's the problem?
it is only h^3
so you have to solve it
then why do you have 3 piV multiplied by h?
i dodn't undeand rst
you have 3piVh ^3 right?
yes of course
you want to solve the equation?
but your question is unfortunately unclear, what is excatly that you want?
SEE i am giving you V= 1/3 * pi * r^2 * h
AND S = pi^2r^2(root of (r^2 + h^2))
so you don't know the answer of only 8th standard
no now, I got you. :)
excuse me, you're the one who asked for help, why are you being so boiled up? It's rude, please be polite.
all you have to do is substitute V and S in the equation and simplify.
THIS IS THE PROBLEM THAT I M FACING THE ANSWER IS NOT IN OPTIONS
and when you do that you get in the end.\[\pi^2r^2h^4 - 4\pi r^4h^2(r^2 + h^2) + 1/3 \pi r^2h\]
yes i did that
ofcourse you won't get it corret in the first place, try again. What are the options, tell me?
okey i m giving the options
1) option - 2
2) option - 0
3) option - 2pi
4) option - 3(pi)^2
I've made a mistake, in the end of the answer I gave you above it's supposed to be \[3\pi r^2h\] and note 1/3 pir^2h
the answer is 0 !
here the solution is : first you'll substitute the given in the formula and you will end up with this: \[\pi^2 r^2h^4 - 4 \pi^2r^4h^2(r^2 + h^2) + \pi^2r^4h^2\] then simplify, it's a long step but in the end you will end up with : \[-3\pi^2r^2h^4 - 3\pi^2r^2h^2\] = \[-3\pi^2h^2(r^2h^2 - r^2h^2)\] = \[-3\pi^2h^2\] x 0 = 0 That's it :)
wait that's wrong >_<
this has caused me a headache._.