if h,s, V be the height, Curved surface area and volume of a cone respectively then 3piVh^3 - s^2h^2 + 9V^2 is:
NOTE PI = 22/7 or 3.14

- anonymous

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- anonymous

sstarica do u want options

- anonymous

you mean \[(3\pi Vh)^3 - s^2h^2 + 9V^2\]
so what's the problem?

- anonymous

no sstarica

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## More answers

- anonymous

it is only h^3

- anonymous

so you have to solve it

- anonymous

then why do you have 3 piV multiplied by h?

- anonymous

i dodn't undeand
rst

- anonymous

you have 3piVh ^3 right?

- anonymous

yes of course

- anonymous

you want to solve the equation?

- anonymous

yes

- anonymous

but your question is unfortunately unclear, what is excatly that you want?

- anonymous

SEE i am giving you V= 1/3 * pi * r^2 * h

- anonymous

lol

- anonymous

AND S = pi^2r^2(root of (r^2 + h^2))

- anonymous

so you don't know the answer of only 8th standard

- anonymous

no now, I got you. :)

- anonymous

oh k

- anonymous

ANSWER IT

- anonymous

excuse me, you're the one who asked for help, why are you being so boiled up? It's rude, please be polite.

- anonymous

okey

- anonymous

all you have to do is substitute V and S in the equation and simplify.

- anonymous

THIS IS THE PROBLEM THAT I M FACING THE ANSWER IS NOT IN OPTIONS

- anonymous

and when you do that you get in the end.\[\pi^2r^2h^4 - 4\pi r^4h^2(r^2 + h^2) + 1/3 \pi r^2h\]

- anonymous

yes i did that

- anonymous

ofcourse you won't get it corret in the first place, try again.
What are the options, tell me?

- anonymous

okey i m giving the options

- anonymous

1) option - 2

- anonymous

2) option - 0

- anonymous

3) option - 2pi

- anonymous

4) option - 3(pi)^2

- anonymous

I've made a mistake, in the end of the answer I gave you above it's supposed to be \[3\pi r^2h\] and note 1/3 pir^2h

- anonymous

not*

- anonymous

the answer is 0 !

- anonymous

here the solution is :
first you'll substitute the given in the formula and you will end up with this:
\[\pi^2 r^2h^4 - 4 \pi^2r^4h^2(r^2 + h^2) + \pi^2r^4h^2\]
then simplify, it's a long step but in the end you will end up with :
\[-3\pi^2r^2h^4 - 3\pi^2r^2h^2\]
= \[-3\pi^2h^2(r^2h^2 - r^2h^2)\]
= \[-3\pi^2h^2\] x 0
= 0
That's it :)

- anonymous

wait that's wrong >_<

- anonymous

this has caused me a headache._.

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