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anonymous
 5 years ago
2y(y^23y2)3(5y+2y^2y^3)
anonymous
 5 years ago
2y(y^23y2)3(5y+2y^2y^3)

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sandra
 5 years ago
Best ResponseYou've already chosen the best response.0ok so you need to distribute out each term

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0so 1. 2y(y^23y2) = (2y*y^2)  (2y *3y)  (2y*2) = 2y^3 6y^2 4y

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0id "factor" out each term; but feel free to distribute them out :)

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0well I'll do it this way, then you sow that way =)

sandra
 5 years ago
Best ResponseYou've already chosen the best response.02. 3(5y+2y^2y^3) = (3*5y) + (3*2y^2)  (3*y^3) = 15y + 6y^2  3y^3

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0now subtract them: 2y^3 6y^2 4y  (15y + 6y^2  3y^3) = 2y^3 6y^2 4y 15y 6y^2 +3y^3

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0and combine like terms (all of the y's, y^2 and y^3): y^3 12y^2 19y

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0first one is 5y^3 heh, since 2+3=5, not 1 =)

sandra
 5 years ago
Best ResponseYou've already chosen the best response.0so I get 5y^3 12y^2 19y
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